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Lera25 [3.4K]
3 years ago
11

PLS HELPPP! Why are ions harmful and why are they not harmful?

Physics
2 answers:
bonufazy [111]3 years ago
6 0

Answer:

Ions can be harmful because ions can produce dangerous indoor ozone and  can waste space and electricity. Hours of negative ion exposure can produce symptoms of depression. On the other hand, ions can help improve our immune systems by strengthening our immune cells. Ions can also speed up the production of antibiotics.

Fittoniya [83]3 years ago
5 0

Answer:

This is because we are surrounded by positive ions from electromagnetic fields generated by computers, cell phones, and other electronic devices which can impair brain function and suppress the immune system causing symptoms such as: anxiety, breathing difficulty, fatigue, headaches, irritability, lack of energy, poor concentration, nausea, and vertigo,

Explanation:

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Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat thi
tatiyna

If the lightbulb A in the circuit shown in the image burned out, the path for the  current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.

If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.

8 0
4 years ago
An infinite conducting cylindrical shell of outer radius r1 = 0.10 m and inner radius r2 = 0.08 m initially carries a surface ch
irinina [24]

Answer:

a) \sigma_{\rm in} = -2.18~{\rm \mu C/m^2}

b) \sigma_{\rm out}= 1.12~{\rm \mu C/m^2}

c) E = \frac{\sigma(r_1 + r_2)}{\epsilon_0 r}

Explanation:

Before the wire is inserted, the total charge on the inner and outer surface of the cylindrical shell is as follows:

Q_{\rm in} = \sigma A_{\rm in} = \sigma(2\pi r_1 h) = (-0.35)(2\pi (0.08) h) = -0.175h~{\rm \mu C}

Q_{\rm out} = \sigma A_{\rm out} = \sigma(2\pi r_2 h) = (-0.35)(2\pi (0.1) h) = -0.22h~{\rm \mu C}

Here, 'h' denotes the length of the cylinder. The total charge of the cylindrical shell is -0.395h μC.

When the thin wire is inserted, the positive charge of the wire attracts the same amount of negative charge on the inner surface of the shell.

Q_{\rm wire} = \lambda h = 1.1h~{\rm \mu C}

a) The new charge on the inner shell is -1.1h μC. Therefore, the new surface charge density of the inner shell can be calculated as follows:

\sigma_2 = \frac{Q_{\rm in}}{2\pi r_1h} = \frac{-1.1h}{2\pi r_1 h} = \frac{-1.1}{2\pi(0.08)} = -2.18~{\rm \mu C/m^2}

b) The new charge on the outer shell is equal to the total charge minus the inner charge. Therefore, the new charge on the outer shell is +0.705 μC.

The new surface charge density can be calculated as follows:

\sigma_{\rm out}= \frac{Q_{\rm out}}{2\pi r_2h} = \frac{0.705h}{2\pi r_2 h} = \frac{0.705}{2\pi(0.1)} = 1.12~{\rm \mu C/m^2}

c) The electric field outside the cylinder can be found by Gauss' Law:

\int{\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

We will draw an imaginary cylindrical shell with radius r > r2. The integral in the left-hand side will be equal to the area of the imaginary surface multiplied by the E-field.

E(2\pi r h) = \frac{Q_{\rm enc}}{\epsilon_0}\\E2\pi rh = \frac{\sigma 2\pi (r_1 + r_2)h}{\epsilon_0}\\E = \frac{\sigma(r_1 + r_2)}{\epsilon_0 r}

4 0
3 years ago
Write a short narrative from the perspective of a mineral moving through the rock cycle. The mineral must undergo at least four
Art [367]

Answer: Mineral and non- mineral components circulate in the environment in different forms whether it is in the form of solid, liquid, or gas.

Explanation:

Plants take up the minerals like calcium, potassium, nitrogen, sulphur, and others from the soil and utilize them for their survival and growth. These minerals are stored in the flowers, leaves, roots, and other plant parts and these plant parts are consumed by humans and animals. So, inorganic minerals from the soil are converted into organic forms by the plants again the minerals are decomposed into inorganic forms after the death of organisms and again mineral is converted into inorganic form in the soil and these minerals can become the component of the rocks after the sedimentation of the soil.

3 0
3 years ago
Which is the best example of a scientific discovery resulting from new technology?
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third

Explanation:

i think so because finding structure of dna can help a lot for well being of human being

8 0
3 years ago
The process by which beach sediment moves down the beach with the current is called ​
irinina [24]

Answer:

Longshore drift

Explanation:

As waves repeatedly hit the beach, some of the beach sediment moves down the beach with the current, in a process called Longshore drift. A spit is a beach that projects like a finger out into the water. A sand dune is a deposit of wind-blown sand.

PLEASE MARK BRAINLIEST!!

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