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astraxan [27]
3 years ago
10

Of the following substances, an aqueous solution of ________ will form basic solutions. NH4Br Pb(NO3)2 K2CO3 NaF

Chemistry
1 answer:
KatRina [158]3 years ago
5 0

Answer:

K2CO3  and NaF

Explanation:

In order to ascertain which salt would form a basic solution we have to identify the classification of each of the salts.

- NH4Br: is the salt of a weak base (NH3) and a strong acid (HBr). This means that it would form an acidic solution.

- Pb(NO3): This is a normal salt, hence would not form a basic solution.

-  K2CO3: This is salt that forms a strongly alkaline/basic solution.

- NaF: it is the salt of a strong base, NaOH, and a weak acid, HF. This means this would form a basic solution.

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(d) What is the mass percentage of water in CdCl2.4H2O?​
Zielflug [23.3K]

The mass percentage of water (H₂O) in cadmium chloride tetra hydratesolution is equal to the 28.2%.

<h3>How do we calculate mass percentage?</h3>

Mass percentage of any substabce present in any solution will be calculated as:
Mass percent = (Mass of substance/Total mass of solution)×100%

According to the question,

Mass of water (H₂O) = 18.02 g/mol

Mass of solvent (CdCl₂.4H₂O) = 183.32 + 4(18.02) = 255.4 g/mol

On putting values, we get

Mass percent = (18.02 / 255.4) × 100% = 28.2%

Hence mass percent of water is 28.2%.

To know more about mass percent, visit the below link:

brainly.com/question/13896694

6 0
2 years ago
Read 2 more answers
Given that the density of TlCl(s) is 7.00 g/cm3 and that the length of an edge of a unit cell is 385 pm, determine how many form
ryzh [129]
Here's my best guess
the volume of the unit cell is (385*10^-12)^3=5.7066*10^-29 m^3
multiply by density to get mass mass = (7 g/cm^3)*(100^3 cm^3 / 1^3 m^3) * 5.7066*10^-29 m^3= 3.99466*10^-22 g
covert to moles 3.99466*10^-22 g * 1 mol / 239.82 g = 1.6657 *10^-24 mol
convert to number of units

1.6657 *10^-24 mol * 6.23*10^23 units/mol = 1.04

385 pm = 3.85*10^(-8) cm

The volume of the unit cell is the cube of that, which is 5.71*10^(-23) cm^3. Since the ratio of mass to volume (i.e. the density) must be the same no matter what amount of TlCl you have, you can say:
7 = x/(5.71*10^(-23)), where x is the mass of the unit cell. Solving for x, you get 4*10^(-22) g.

The mass of a molecule of TlCl is 240 amu, which in grams is 4*10^(-22) g. The mass of the unit cell and the mass of a molecule of TlCl is the same. Therefore there is one formula unit of TlCl per unit cell.

3 0
3 years ago
How many grams are in 3 moles of HF? Help please!! 20 points!
Svetllana [295]

It would be 60.03 grams

5 0
3 years ago
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Keith_Richards [23]

Answer:

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Explanation:

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dmitriy555 [2]

Answer:

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