1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergey [27]
3 years ago
14

1. A composite when tested bounces half as high as the original material. How can

Physics
1 answer:
Mkey [24]3 years ago
7 0

I creating another composite to jump one-quarter as high as the initial composite you most bear in mind factors of weight,hardness ,center of mass will be one-quarter of the prior composite in other for it to bounces only one-quarter .

From the question we are told

A composite when tested bounces half as high as the original material. How can  you create another composite that bounces only one-quarter as high

Generally We know that

A composite Material is a material that is made up of more than be substance i.e is it requires substance of variant properties and make up to come together to form it.

Therefore

I creating another composite to jump one-quarter as high as the initial composite you most bear in mind factors of weight,hardness ,center of mass will be one-quarter of the prior composite in other for it to bounces only one-quarter

For more information on this visit

brainly.com/question/13025901?referrer=searchResults

You might be interested in
Two 2.0kg bodies A and B collide The velocities before the collision are U1=15i+30j and U2=-10j+5.0j After the collision V1=-5.0
Svetllana [295]

Use the law of conservation of momentum. Since the momentum is a linear measure, we can treat each of the dimension separately:

i-direction:

m_1u_{1i}+m_2u_{2i}=m_1v_{1i}+m_2v_{2i}\\v_{2i} = \frac{m_1u_{1i}+m_2u_{2i}-m_1v_{1i}}{m_2}=\frac{(2\cdot 15-2\cdot10+2\cdot5)kg\frac{m}{s}}{2kg}=10\frac{m}{s}

j-direction:

m_1u_{1j}+m_2u_{2j}=m_1v_{1j}+m_2v_{2j}\\v_{2j} = \frac{m_1u_{1j}+m_2u_{2j}-m_1v_{1j}}{m_2}=\frac{(2\cdot 30+2\cdot5-2\cdot20)kg\frac{m}{s}}{2kg}=15\frac{m}{s}

Answer: Final velocity is: (10i + 15j) m/s

Change in the kinetic energy:

\Delta E_k = E_{ku}-E_{kv} = \frac{1}{2}m(u_1^2+u_2^2-v_1^2-v_2^2)=\\=\frac{1}{2}2kg(1125+125-425-325)\frac{m^2}{s^2}=500J

Answer: The system lost 500J worth of kinetic energy in the collision

4 0
3 years ago
A car traveling 90km/hr is 100 m behind a truck traveling 50km/hr. How long will it take the car to reach the truck?
AlexFokin [52]

The faster car behind is catching up/closing the gap/gaining on
the slow truck in front at the rate of (90 - 50) = 40 km/hr.

At that rate, it takes (100 m) / (40,000 m/hr) = 1/400 of an hour
to reach the truck.

(1/400 hour) x (3,600 seconds/hour) = 3600/400 = <em>9 seconds</em>, exactly 


4 0
3 years ago
Read 2 more answers
Need help with this<br> THANKS TO WHO HELPS &lt;3
nekit [7.7K]

Answer:

because it's north

Explanation:

u if yyggggggggggggggg hgfth

8 0
2 years ago
Read 2 more answers
A playground merry-go-round has radius 2.40 m and moment of inertia 2100 kg⋅m2 about a vertical axle through its center, and it
daser333 [38]

Answer:

a) 0.31 rad/s

b) 100 J

c) 6.67 W

Explanation:

(a) the force would generate a torque of:

T = FR = 18 * 2.4 = 43.2 Nm

According to Newton 2nd law, the angular acceleration would be

\alpha = \frac{T}{I} = \frac{43.2}{2100} = 0.021 rad/s^2

It starts from rest, then after 15s it would achieve a speed of

\omega = \alpha t = 0.021 * 15 = 0.31 rad/s

(b) The distance angle swept by it is:

\theta = \frac{\alpha t^2}{2} = \frac{0.021 * 15^2}{2} = 2.314 rad

Hence the work by the child

W = T\theta = 43.2 *2.314  \approx 100 J

c) Average power to work per time unit

P = \frac{W}{t} = \frac{100}{15} = 6.67 W

7 0
2 years ago
The pulley system below uses a gasoline engine to raise a drill head up through a smooth drill pipe. The engine provides a const
polet [3.4K]

NB: The diagram of the pulley system is not shown but the information provided is sufficient to answer the question

Answer:

Power = 2702.56 W

Explanation:

Let the power consumed be P

Energy expended = E = mgh

height, h = 5 m

E = 80 * 9.8 * 5

E = 3920 J

Power = \frac{Energy}{time}

To calculate the time, t

From F = ma

F = 900 N

900 = 80 a

a = 900/80

a = 11.25 m/s²

From the equation of motion, s = ut + 0.5at^{2}

The drill head starts from rest, u = 0 m/s

5 = 0 * t + (0.5*11.25*t^{2} )\\5 = 5.625t^{2}\\t^{2} = 5/5.625\\t^{2} = 0.889\\t = 0.943 s

Power, P = E/t

P = 3920/0.0.943

P = 4157.79 W

But Efficiency, E = 0.65

P = 0.65 * 4157.79

Power = 2702.56 W

6 0
2 years ago
Other questions:
  • A 9.0-kg box of oranges slides from rest down a frictionless incline from a height of 5.0 m. A constant frictional force, introd
    8·1 answer
  • A strong man is compressing a lightweight spring between two weights. One weight has a mass of 2.3 kgkg , the other a mass of 5.
    6·1 answer
  • A positive point charge q1 = +5.00 × 10−4C is held at a fixed position. A small object with mass 4.00×10−3kg and charge q2 = −3.
    6·1 answer
  • What is the date of birth for 14
    9·2 answers
  • The relationship between gas pressure and gas volume is described by ________.
    7·2 answers
  • Calculate the resistance of a 900.-watt toaster
    13·2 answers
  • A 6.0 cm candle is 30.0 cm from a concave mirror that has a focal length of 11 cm. What is the distance of the image from the mi
    10·1 answer
  • 100 J OF HEAT IS PRODUCED EACH SECOND IN A 4 COULUMB RESISTER. THE POTENTIAL DIFFERANCE ACROSS THE RESISTER WILL BE
    9·1 answer
  • what happens to the strength of an electromagnet when the number of coils in the solenoid is decreased?
    15·2 answers
  • 1.Una partícula de masa m = 0.2 [kg] está unido a dos resortes idénticos (de longitud L = 1.2 [m]) sobre la parte superior de un
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!