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sergey [27]
3 years ago
14

1. A composite when tested bounces half as high as the original material. How can

Physics
1 answer:
Mkey [24]3 years ago
7 0

I creating another composite to jump one-quarter as high as the initial composite you most bear in mind factors of weight,hardness ,center of mass will be one-quarter of the prior composite in other for it to bounces only one-quarter .

From the question we are told

A composite when tested bounces half as high as the original material. How can  you create another composite that bounces only one-quarter as high

Generally We know that

A composite Material is a material that is made up of more than be substance i.e is it requires substance of variant properties and make up to come together to form it.

Therefore

I creating another composite to jump one-quarter as high as the initial composite you most bear in mind factors of weight,hardness ,center of mass will be one-quarter of the prior composite in other for it to bounces only one-quarter

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A laser pulse of duration 25 ms has a total energy of 1.4 J. The wavelength of this radiation is
SpyIntel [72]

Answer:

n = 4 x 10¹⁸ photons

Explanation:

First, we will calculate the energy of one photon in the radiation:

E = \frac{hc}{\lambda}\\\\

where,

E = Energy of one photon = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m

Therefore,

E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}

E = 3.505 x 10⁻¹⁹ J

Now, the number of photons to make up the total energy can be calculated as follows:

Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\

<u>n = 4 x 10¹⁸ photons</u>

8 0
3 years ago
Which groups of organisms became extinct during the Paleozoic Era
guapka [62]
Dinosaurs but I need the whole groups yo tell you ;)
4 0
3 years ago
A driver who does not wear a seat belt continues to move at the initial velocity until she or he hits something solid (e.g the s
egoroff_w [7]

This question is incomplete, the complete question is;

Seatbelts provide two main advantages in a car accident (1) they keep you from being thrown from the car and (2) they reduce the force that acts on your during the collision to survivable levels. This second benefit can be illustrated by comparing the net force encountered by a driver in a head-on collision with and without a seat beat.  

1) A driver wearing a seat beat decelerates at roughly the same rate as the car it self. Since many modern cars have a "crumble zone" built into the front of the car, let us assume that the car decelerates of a distance of 1.1 m. What is the net force acting on a 70 kg driver who is driving at 18 m/sec and comes to rest in this distance?

Fwith belt =

2) A driver who does not wear a seat belt continues to move at the initial velocity until she or he hits something solid (e.g the steering wheel) and then comes to rest in a very short distance. Find the net force on a driver without seat belts who comes to rest in 1.1 cm.

Fwithout belt =

Answer:

1) The Net force on the driver with seat belt is 10.3 KN

2) the Net force on the driver without seat belts who comes to rest in 1.1 cm is 1030.9 KN

Explanation:

Given the data in the question;

from the equation of motion, v² = u² + 2as

we solve for a

a = (v² - u²)/2s ----- let this be equation 1

we know that, F = ma ------- let this be equation 2

so from equation 1 and 2

F = m( (v² - u²)/2s )

where m is mass, a is acceleration, u is initial velocity, v is final velocity and s is the displacement.

1)

Wearing sit belt, car decelerates of a distance of 1.1 m. What is the net force acting on a 70 kg driver who is driving at 18 m/sec and comes to rest in this distance.

i.e, m = 70 kg, u = 18 m/s, v = 0 { since it came to rest }, s = 1.1 m

so we substitute the given values into the equation;

F = 70( ((0)² - (18)²) / 2 × 1.1 )

F = 70 × ( -324 / 2.4 )

F = 70 × -147.2727

F = -10309.09 N

F = -10.3 KN

The negative sign indicates that the direction of the force is opposite compared to the direction of the motion.

Fwith belt =  10.3 KN

Therefore, Net force of the driver is 10.3 KN

2)

No sit belt,  

m = 70 kg, u = 18 m/s, v = 0 { since it came to rest }, s = 1.1 cm = 1.1 × 10⁻² m

we substitute

F = 70( ((0)² - (18)²) / 2 × 1.1 × 10⁻² )

F = 70 × ( -324 / 0.022 )

F = 70 × -14727.2727

F = -1030909.08 N

F = -1030.9 KN

The negative sign indicates that the direction of the force is opposite compared to the direction of the motion.

Fwithout belt = 1030.9 KN

Therefore, the net force on the driver without seat belts who comes to rest in 1.1 cm is 1030.9 KN

4 0
3 years ago
Help me pleaseee, it’s due today: Two people push on a large gate as shown on the view from above in the diagram. If the moment
Sladkaya [172]

Answer:

the angular acceleration of the gate is approximately 1.61  \frac{rad}{s^2}

Explanation:

Recall the formula that connects the net torque with the moment of inertia of a rotating object about its axis of rotation, and the angular acceleration (similar to Newton's second law with net force, mass, and linear acceleration):

\sum \tau_1=I\,\alpha

In our case, both forces contribute to the same direction of torque, so we can add their torques up and get the net torque on the gate:

\tau_{net}=(20*2+30*3.5) \,N\,m=145\,\,N\,m

Now we use this value to obtain the angular acceleration by using the given moment of inertia of the rotating gate:

\sum \tau_1=I\,\alpha\\145\,\,N\.m=(90\,\,kg\,m^2)\,\alpha\\\alpha= \frac{145}{90} \frac{rad}{s^2} = 1.61\, \frac{rad}{s^2}

4 0
3 years ago
11) Which statement about covalent bonds is true? A) Covalent bonds are generally weaker than ionic bonds because they form full
Cerrena [4.2K]
<h3><u>Answer;</u></h3>

C) Covalent bonds are generally weaker than ionic bonds because they overlap electrons to fill their outer shell.

<h3><u>Explanation;</u></h3>
  • <em><u>Covalent bond is a type of bond that results from the sharing of electrons between two non-metal atoms. </u></em>
  • <em><u>Ionic bond on the other is a type of bond that results from the transfer of electrons between metal atoms and non metal atoms, where a metal atom looses electrons and a non-metal atom gains electrons.</u></em>
  • <em><u>The amount of energy required to break an given bond determines how strong a particular bond is.</u></em> Ionic bonds require more energy to break as compared to covalent bond and therefore they are stronger than the covalent bonds.
5 0
3 years ago
Read 2 more answers
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