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3 years ago

A passenger jet flies from one airport to another 1273 miles away in 2.7 h. Find its average speed.

Physics

1 answer:

AnnZ [28]3 years ago

3 0

Answer:

Average speed of passenger jet

$s = 471.48\ mi/hr$

Explanation:

Let s be the average speed of the passenger jet.

Given:

Distance from one airport to another airport $d = 1273\ mi$

Total time taken $t = 2.7\ hr$

We need to find the average speed of the passenger jet.

Solution:

Average speed formula:

The ratio of the total distance travelled by the object to the time taken to cover that distance.

$Average\ speed = \frac{Total\ distance\ travelled}{Total\ time\ taken}$

$s = \frac{d}{t}$

Substitute total distance and time value in above equation.

$s = \frac{1273}{2.7}$

$s = 471.48\ mi/hr$

Therefore, the average speed of the passenger jet is $s = 471.48\ mi/hr$ .

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A passenger jet flies from one airport to another 1273 miles away in 2.7 h. Find its average speed.​

A passenger jet flies from one airport to another 1273 miles away in 2.7 h. Find its average speed.