Answer:
Part 1: It would be a straight line, current will be directly proportional to the voltage.
Part 2: The current would taper off and will have negligible increase after the voltage reaches a certain value. Graph attached.
Explanation:
For the first part, voltage and current have a linear relationship as dictated by the Ohm's law.
V=I*R
where V is the voltage, I is the current, and R is the resistance. As the Voltage increase, current is bound to increase too, given that the resistance remains constant.
In the second part, resistance is not constant. As an element heats up, it consumes more current because the free sea of electrons inside are moving more rapidly, disrupting the flow of charge. So, as the voltage increase, the current does increase, but so does the resistance. Leaving less room for the current to increase. This rise in temperature is shown in the graph attached, as current tapers.
Answer:
B.29
Explanation:
In general purpose acme thread:
Nominal depth of thread=0.5
Included angle =29 degrees
Generally Acme thread are following types
1.General purpose(G) Acme
2.Centralizing(C) Acme
3. Stub Acme
Centralizing(C) Acme threads have tighter tolerance during manufacturing as compare to General purpose(G) Acme threads.
Answer:
Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source. ... If one of the parallel paths is broken, current will continue to flow in all the other paths.
Answer :
<h3>Flow rate in pipe B is = 0.3094
</h3>
Explanation:
Given :
Length of pipe A 
m
Length of pipe B 
m
Flow rate through pipe A 
Diameter of pipe 
m
Velocity from pipe A,
Here, head loss is same because height is same.
Now rate of flow from pipe B is,
Answer:
v = 21.409 m/s
Explanation:
Given data:
Total weight of the platform and weight together, W = 900 N
Diameter of the water jet = 5 cm = 0.05 m
Now,
the force exerted by the water jet is balancing the platform
also,
Force exerted by the water jet = ρAv²
where,
ρ is the density of the water = 1000 kg/m³
A is the area of the outlet of the jet = 
or
A = 0.00196 m²
v is the velocity of the jet
thus,
W = ρAv²
or
900 = 1000 × 0.00196 × v²
or
v = 21.409 m/s
Hence, the velocity of the jet is 21.409 m/s
