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storchak [24]
3 years ago
12

Calculate pressure at the mid-plane of an annular cylinder of iron powder pressed using double-action press. The punch pressure

(i.e., applied pressure) is 100 MPa when the height of the pressed sample is 10 cm. The coefficient of friction is 0.1, radial-to-axial pressure ratio is 0.4, and the wall thickness of the annular compact is 2 cm.

Engineering
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

81.87

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

Solution as an attached file.

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Name the main classes of polymer and define their characteristic properties
Svetlanka [38]

Answer:

Polymers are the naturally occurring or synthetic macromolecules that are composed of repeating subunits, called monomers.

The three main classes of polymers are: thermoplastic, thermosetting, and the elastomers.

Thermoplastic polymers have linear bonding. These polymers can be melted again and thus can recycled.

Thermosetting polymers have cross-linked bonding. These polymers decompose when heated and thus can not be remelted and recycled.

Elastomers have linear bonding with some cross-linking. These polymers extreme elastic extensibility and thus can revert back to its original shape after deformation, without causing any permanent damage.

8 0
3 years ago
Technician A says a basic circuit problem can be caused by something in the circuit that increases voltage. Technician B says a
Harrizon [31]

Answer:

  both are

Explanation:

It depends on what the symptoms of the "basic circuit problem" are. Both overvoltage and shorts are the kinds of things that can cause circuit damage, and either can be the cause of the other.

7 0
3 years ago
To increase fault-tolerance, the security administrator for Corp has installed an active/passive firewall cluster where the seco
zheka24 [161]

Answer:

Inbound packets are traversing the active firewall and return traffic is being sent through the passive firewall

Explanation:

5 0
3 years ago
A train which is traveling at 70 mi/hr applies its brakes as it reaches point A and slows down with a constant deceleration. Its
Ugo [173]

Answer:

a) 0 mi/s^2

b) 52 mi/s

Explanation:

Assuming the crossing is 1/2 mile past point A and that point B is near point A (it isn't clear in the problem)

The train was running at 70 mi/h at point A and with constant deceleration reachesn the crossing 1/2 mile away with a speed of 52 mi/h

The equation for position under constant acceleration is:

X(t) = X0 + V0 * t + 1/2 * a * t^2

I set my reference system so that the train passes point A at t=0 and point A is X = 0, so X0 = 0.

Also the equation for speed under constant acceleration is:

V(t) = V0 + a * t

Replacing

52 = 70 + a * t

Rearranging

a * t = 52 - 70

a = -18/t

I can then calculate the time it will take it to reach the crossing

1/2 * a * t^2 + V0 * t  - X(t) = 0

Replacing

1/2 (-18/t) * t^ + 70 * t - 1/2 = 0

-9 * t + 70 * t = 1/2

61 * t = 1/2

t = (1/2)/61 = 0.0082 h = 29.5 s

And the acceleration is:

a = -18/0.0082 = -2195 mi/(h^2)

To beath the train the car must reach the crossing in 29.5 - 4.3 = 25.2 s

X(t) = X0 + V0 * t + 1/2 * a * t^2

52 mi/h = 0.0144 mi/s

1/2 = 0 + 0.0144 * 25.2 + 1/2 * a * 25.2^2

1/2 = 0.363 + 317.5 * a

317.5 * a = 0.5 - 0.363

a = 0.137/317.5 = 0.00043 mi/s^2 (its almost zero)

The car should remain at about constant speed.

It will be running at the same speed.

4 0
3 years ago
Determine the maximum volume in gallons​ [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of 3
Olin [163]

Answer:

V=1601gal

Explanation:

Hello! This problem is solved as follows,

First we must raise the equation that defines the pressure at the bottom of the tank with the purpose of finding the height that olive oil reaches.

This is given as the sum due to the atmospheric pressure (1atm = 101.325kPa), and the pressure due to the weight of the olive oil, taking into account the above, the following equation is inferred.

P=Poil+Patm

P=total pressure or absolute pressure=26psi=179213.28Pa

Patm= the atmospheric pressure =101325Pa

Poil=pressure due to the weight of olive oil=0.86αgh

α=density of water=1000kg/m^3

g=gravity=9.81m/s^2

h= height that olive oil reaches

solving

P=Poil+Patm

P=Patm+0.86αgh

h=\frac{P-Patm}{0.86\alpha g } =\frac{179214.28-101325}{(0.86)(1000)(9.81)} \\h=9.23m[/tex]

Now we can use the equation that defines the volume of a cylinder.

V=V=\frac{\pi }{4} D^{2} h

D=3ft=0.9144m

h=9.23m

solving

V=\frac{\pi }{4} (0.9144)^{2} 9.23=6.06m^3

finally we use conversion factors to find the volume in gallons

V=6.06m^3\frac{1000L}{1m^3} \frac{1gal}{3.785L} =1601gal

3 0
3 years ago
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