Answer:
- the mass flow rate of air is 7.53 kg/s
- the exit area is 0.108 m²
Explanation:
Given the data in the question;
lets take a look at the steady state energy equation;
m" = W"
/ [ (h₁ - h₂ ) -
]
Now at;
T₁ = 900K, h₁ = 932.93 k³/kg
T₂ = 500 K, h₂ = 503.02 k³/kg
so we substitute, in our given values
m" = [ 3200 kW × 
] / [ (932.93 - 503.02 )k³/kg -
|
||
| ]
m" = 7.53 kg/s
Therefore, the mass flow rate of air is 7.53 kg/s
now, Exit area A₂ = v₂m" / V₂
we know that; pv = RT
so
A₂ = RT₂m" / P₂V₂
so we substitute
A₂ = {[ 
×
×
] / [(1 bar)(100 m/s )]} |
||
A₂ = 0.108 m²
Therefore, the exit area is 0.108 m²
Answer:
In the steel: 815 kPa
In the aluminum: 270 kPa
Explanation:
The steel pipe will have a section of:
A1 = π/4 * (D^2 - d^2)
A1 = π/4 * (0.8^2 - 0.7^2) = 0.1178 m^2
The aluminum core:
A2 = π/4 * d^2
A2 = π/4 * 0.7^2 = 0.3848 m^2
The parts will have a certain stiffness:
k = E * A/l
We don't know their length, so we can consider this as stiffness per unit of length
k = E * A
For the steel pipe:
E = 210 GPa (for steel)
k1 = 210*10^9 * 0.1178 = 2.47*10^10 N
For the aluminum:
E = 70 GPa
k2 = 70*10^9 * 0.3848 = 2.69*10^10 N
Hooke's law:
Δd = f / k
Since we are using stiffness per unit of length we use stretching per unit of length:
ε = f / k
When the force is distributed between both materials will stretch the same length:
f = f1 + f2
f1 / k1 = f2/ k2
Replacing:
f1 = f - f2
(f - f2) / k1 = f2 / k2
f/k1 - f2/k1 = f2/k2
f/k1 = f2 * (1/k2 + 1/k1)
f2 = (f/k1) / (1/k2 + 1/k1)
f2 = (200000/2.47*10^10) / (1/2.69*10^10 + 1/2.47*10^10) = 104000 N = 104 KN
f1 = 200 - 104 = 96 kN
Then we calculate the stresses:
σ1 = f1/A1 = 96000 / 0.1178 = 815000 Pa = 815 kPa
σ2 = f2/A2 = 104000 / 0.3848 = 270000 Pa = 270 kPa
Answer:
perpetual motion machine of second type is a machine that generates job from a single source of heat.
Explanation:
perpetual motion machine is a machine that generates job from a single source of heat. only one heat reservoir is present in this type of machine and it is continuously cooled to generate function without transferring heat to a cooler reservoir. Such a demonstration machine was names as ammonia engine
Answer:According to NEC 220.12,
“the floor area shall be calculated from outside dimensions of the buildings, dwelling unit, or other area involved.
The area should not include open porches, garages or unused or unfinished spaces not adaptable for future use”.
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Explanati
Answer:
The option that identifies why the bicycle cannot yet be created as a model in the scenario is;
Suzanne forgot to include the exact units of measurement that should be used
Explanation:
The design sketch turned over to the team that will work on the prototype by Suzanne should present all aspects of the design that will enable others working on the design and that make use of the sketch to have a clear understanding of what is required of them
Given that Suzanne has included the numbers that explain the relationship between the sketch and the real world object, the scale that shows the ratios and proportions of the sketch and the actual bicycle has been provided, however, given that the the machinist still need more information, the units of the measurement indicated in the drawing was not included, therefore, the actual dimensions and size that gives the length of the parts of the sketch and of the prototype to be made cannot be determined.
