Answer:
The answer is 4.905 dB
Explanation:
Let say that that signal is sinusoidal i.e Am sin(wt)
Hence the power of the signal
From the question we are given that Amplitude Am = 10mV
substituting this value into the power formula
Power of the signal μW
From the question we where given that the signal to noise ratio is
Note: The dB of a value means the same thing as 10 log of the value
Now to obtain noise power we make it the subject in the above equation
μW
Now to obtain the overall signal gain we multiply the individual gain for the frequency that we are considering i.e 1KHz as our signal
Overall signal gain =
Now that we have gotten this we can now compute the output signal power gain denoted by
W
Now to obtain the overall signal gain we multiply the individual gain for the frequency that we are considering i.e 10KHz as our noise
Output signal to noise ratio (S/N) =
Answer:
so hard it is
Explanation:
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Answer:
Applied Stress > 58.29 MPa
Explanation:
- Resolved shear stress should be greater than critically resolved shear stress in order to cause the single crystal to yield
Given angles are
∅ = 42.7 degree
Ф = 48.3 degree
Critically resolved shear stress = 28.5 MPa
If we consider
Critically resolved shear stress = resolved shear stress
Applied stress can be found by
(1)
Applied Stress =
Applied Stress =
Applied Stress = 58.29 MPa
We got reference
- By putting applied stress values of greater than 58.29 MPa in equation 1 we get
Resolved Shear Stress = 60 x Cos(48.3) x Cos(42.7)
Resolved Shear Stress = 29.33 MPa
Therefore, by the above calculation we conclude that applied stress should be greater than 58.29 MPa, In order to make resolved shear stress to be greater than critically resolved shear stress that is essential for single crystal to yield.