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nordsb [41]
2 years ago
11

Which of the following activities can help expand engineers' creative thinking capabilities?

Engineering
2 answers:
Papessa [141]2 years ago
4 0

Answer:   its not team building excercize

Explanation:

Assoli18 [71]2 years ago
3 0

Answer:

team building exercises

Explanation:

You might be interested in
A conical enlargement in a vertical pipeline is 5 ft long and enlarges the pipe diameter from 12 in. to 24 in. diameter. Calcula
makkiz [27]

Answer:

F_y = 151319.01N = 15.132 KN

Explanation:

From the linear momentum equation theory, since flow is steady, the y components would be;

-V1•ρ1•V1•A1 + V2•ρ2•V2•A2 = P1•A1 - P2•A2 - F_y

We are given;

Length; L = 5ft = 1.52.

Initial diameter;d1 = 12in = 0.3m

Exit diameter; d2 = 24 in = 0.6m

Volume flow rate of water; Q2 = 10 ft³/s = 0.28 m³/s

Initial pressure;p1 = 30 psi = 206843 pa

Thus,

initial Area;A1 = π•d1²/4 = π•0.3²/4 = 0.07 m²

Exit area;A2 = π•d2²/4 = π•0.6²/4 = 0.28m²

Now, we know that volume flow rate of water is given by; Q = A•V

Thus,

At exit, Q2 = A2•V2

So, 0.28 = 0.28•V2

So,V2 = 1 m/s

When flow is incompressible, we often say that ;

Initial mass flow rate = exit mass flow rate.

Thus,

ρ1 = ρ2 = 1000 kg/m³

Density of water is 1000 kg/m³

And A1•V1 = A2•V2

So, V1 = A2•V2/A1

So, V1 = 0.28 x 1/0.07

V1 = 4 m/s

So, from initial equation of y components;

-V1•ρ1•V1•A1 + V2•ρ2•V2•A2 = P1•A1 - P2•A2 - F_y

Where F_y is vertical force of enlargement pressure and P2 = 0

Thus, making F_y the subject;

F_y = P1•A1 + V1•ρ1•V1•A1 - V2•ρ2•V2•A2

Plugging in the relevant values to get;

F_y = (206843 x 0.07) + (1² x 1000 x 0.07) - (4² x 1000 x 0.28)

F_y = 151319.01N = 15.132 KN

6 0
3 years ago
A 2-m3insulated rigid tank contains 3.2 kg of carbon dioxide at 120 kPa.Paddle-wheel work is done on the system until the pressu
AleksandrR [38]

Answer:

The change in entropy is found to be 0.85244 KJ/k

Explanation:

In order to solve this question, we first need to find the ration of temperature for both state 1 and state 2. For that, we can use Charles' law. Because the volume of the tank is constant.

P1/T1 = P2/T2

T2/T1 = P2/P1

T2/T1 = 180 KPa/120KPa

T2/T1 = 1.5

Now, the change in entropy is given as:

ΔS = m(s2 - s1)

where,

s2 = Cv ln(T2/T1)

s1 = R ln(V2/V1)

ΔS = change in entropy

m = mass of CO2 = 3.2 kg

Therefore,

ΔS = m[Cv ln(T2/T1) - R ln(V2/V1)]

Since, V1 = V2, therefore,

ΔS = mCv ln(T2/T1)

Cv at 300 k for carbondioxide is 0.657 KJ/Kg.K

Therefore,

ΔS = (3.2 kg)(0.657 KJ/kg.k) ln(1.5)

<u>ΔS = 0.85244 KJ/k</u>

3 0
3 years ago
Why would an aerospace engineer limit the maximum angle of deflection of the control surfaces?
WITCHER [35]

Answer:

You can create high drag which allows a steeper angle without increasing your air speed on landing. you can reduce the length of landing role. Flaps are also used to increase the drag they are retracted when they are not needed. it is adviseable to down he flaps during the time of take off.

4 0
3 years ago
III. During January, at a location in Alaska winds at −27°C can be observed. However, several meters below ground the temperatur
Naya [18.7K]

Answer:

Not possible.

Explanation:

According to second law of thermodynamics, the maximum efficiency any heat engine could achieve is Carnot Efficiency η defined by:

\eta=1-\frac{T_{cold}}{T_{hot}}

Where

T_{hot} and T_{cold} are temperature (in Kelvin) of heat source and heatsink respectively

In our case (I will be using K = 273+°C) :

\eta=1-\frac{-27+273}{14+273}\\=0.1428

In percentage, this is 14.28% efficiency, which is the <em>maximum</em> theoretical efficiency <em>any</em> heat engine could have while working between -27 and 14 °C temperature. Any claim of more efficient heat engine between these 2 temperature are violates the second law of thermodynamics. Therefore, the claim must be false.

6 0
3 years ago
In the case, the software engineers present at the meeting would concern themselves with ________-level strategy
jekas [21]

The level of strategy which the software engineers would concern themselves with would be highly dependent on the nature of the case or situation.

<h3>What is a strategy?</h3>

A strategy can be defined as a set of guiding principles, procedures, actions, and decisions that a business organization or an individual combines, in order to achieve its aim, objectives and goals.

Basically, developing a strategy is essential because it helps to attract new customers and gives a competitive advantage over rivals in the industry.

<h3>The types of strategy.</h3>

In Software engineering, there are different types of strategy used by software engineers and these include:

  • Tactical strategy
  • Product management strategy
  • Lifecycle process strategy
  • Technology strategy
  • Support strategy
  • Customer strategy

Furthermore, there are three (3) main <u>levels</u> of strategy in software engineering and these are:

  1. Business-level strategy
  2. Functional-level strategy
  3. Corporate-level strategy

In this scenario, the level of strategy which the software engineers present at the meeting would concern themselves with would be highly dependent on the nature of the case or situation.

Read more on strategy here: brainly.com/question/26064163

6 0
2 years ago
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