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3 years ago

What did Rosalind Franklin contribute to the understanding of DNA molecules?

Biology

1 answer:

RoseWind [281]3 years ago

5 0

Answer:

The correct answer is A) An image indicating the shape of a DNA molecule. See the explanation below, please

Explanation:

Rosalind Franklin through studies of X-ray diffraction and crystallography, showed the double helix structure of the DNA molecule.

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Where does the oxygen used in cellular respiration end up?

xz_007 [3.2K]

Oxygen used in cellular respiration ends up in ATP Synthesis in Oxidative Phosphorylation.

Explanation:

Since oxygen is the last electron acceptor in Electron transfer chain, the H ions flow through ATP synthase for ATP synthesis. The electrons from the NADH and FADH are pumped from the matrix of mitochondria to inter-membrane space. The energy released due to the proton gradient formed is used for making ATP.

3 0

3 years ago

Number the steps of the binary fission process in correct order

kari74 [83]

Step 1:

The bacterium cell must copy its DNA so the new cells will have DNA. DNA or, deoxyribonucleic acid, has all of the information the bacterium will need to survive, so it is important it gets copied. The DNA is tightly wound so it is in a neat package called a chromosome.

Steps 2 and 3:

The bacterium now grows larger. This allows for some separation between the two DNA copies that are inside the cell. A division develops in the middle of the bacterium. This division eventually completely divides the bacterium in half. This is called cytokinesis.

Step 4:

Each cell is now called a daughter cell and they separate.

The steps of binary fission

binary fission

Binary fission results in two identical daughter cells. This is a type of asexual reproduction, or creating genetically identical offspring. If humans were able to reproduce using binary fission, it would look something like this: your mother or father would grow larger, and inside all of his or her DNA would be copied. Eventually your parent would split in half creating an identical clone.

5 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

What cellular process releases energy by breaking down glucose when oxygen is not available

Ivan

Answer:

Explanation:

because its food that i choke on

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3 years ago

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The process of ____________ increases genetic variability as it produces gametes for sexual reproduction. A) conjugation B) meio

LekaFEV [45]

B) Meiosis-"a type of cell division that results in four daughter cells each with half the number of chromosomes of the parent cell, as in the production of gametes and plant spores." taken from google

7 0

3 years ago

Read 2 more answers