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mr_godi [17]
3 years ago
5

child is 43 inches tall at age 6. For the next few years, the child grows by 2 inches per year. Explain why the child's height a

fter age 6 is a linear function of his age. The child's height after age 6 is a linear function as there is a constant growth rate. Identify the growth rate and initial value. The growth rate is inches/year and the initial value is inches. Using t for time in years since age 6 and H for height in inches, find a formula for H as a linear function of t. H
Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer: H(t) = 43in + (2in/year)*t.

Step-by-step explanation:

At age of 6, the height is 43 inches.

We can define the age of 6 as our t = 0, where t is our variable that represents the number of years after year number 6.

So t = 1 year corresponds to the age of 7 years

t = 2 years corresponds to the age of 8 years, etc.

We know that for the next few years, the child's height will increase by 2 inches per year.

Then at the age of 7, the height will be: 43 in + 2 in

At the age of 8, the height will be: (43in + 2 in) + 2 in = 43in + 2*2in.

And so on, so we can write this as a linear relationship.

H(t) = 43in + (2in/year)*t.

The initial value is the value when t  = 0 years

H(0) = 43in

The initial value is 43 inches.

The growth rate is the coefficient that multiplies the variable, in this case is 2 inches per year or 2 in/year.

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$120 USD is equivalent to £84.55
8 0
3 years ago
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

6 0
3 years ago
4,567.89
In-s [12.5K]

Answer:

I got 40210.1

Step-by-step explanation:

4,567.89+7,894.56=12462.45

12462.45+1,232.45=13694.9

13694.9+1,474.10=15169

15169+2,585.20=17754.2

17754.2+3696.36=21450.56

21450.56+3,214.56=24665.12

24665.12+6,545.65=31210.77

31210.77+7,898.78=39109.55

39109.55+1.100.55=40210.1

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If PQ = QR, find x. NEED HELP.
max2010maxim [7]

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Step-by-step explanation:

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a class with 30 students had an average score of 80 on a test. A class with 20 students had an average score of 90 on the same t
snow_tiger [21]

The average score of all the students in both classes is 84.

<h3>How to calculate the average?</h3>

The class with 30 students had an average score of 80 on a test. The total score will be:

= 30 × 80

= 2400

A class with 20 students had an average score of 90 on the same test. The total score will be:

= 20 × 90

= 1800

Total scores = 2400 + 1800 = 4200

Number of students = 20 + 30 = 50

The average score will be:

= Total score / Total students

= 4200 / 50

= 84

Learn more about average on:

brainly.com/question/24313700

#SPJ1

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1 year ago
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