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eduard
1 year ago
7

The width of a rectangle is 3 less than its length find the width of the rectangle if its perimeter is 26ft

Mathematics
1 answer:
Marta_Voda [28]1 year ago
7 0

The width of rectangle is 5 feet.

Let us assume the length of rectangle to be x. So, the width of rectangle will be (x - 3).

Now, as per the known fact, perimeter, length and width of rectangle are related by the formula -

Perimeter = 2 × (length + width)

Keep the values in formula to find the value of width

26 = 2 × (x + x - 3)

Performing addition of variables inside the bracket

26 = 2 × (2x - 3)

Shifting 2 to other side of equation to find the value of x

2x - 3 = \frac{26}{2}

Performing division to find the value of x

2x - 3 = 13

Shifting 3 to other side of equation to find the value of x

2x = 13 + 3

Performing addition to find the value of x

2x = 16

Shifting 2 as denominator to other side of equation to find the value of x

x = \frac{16}{2}

Performing division to find the value of x

x = 8

So, length of rectangle is 8 feet

Width of rectangle = x - 3

Width of rectangle = 8 - 3

Width of rectangle = 5 feet

Hence, the width of rectangle is 5 feet.

Learn more about calculation involving rectangle -

brainly.com/question/24571594

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Need math help please!!
s2008m [1.1K]
Just by looking at it, 2 seems to be the correct answer. I mean if you think about it, when the triangle is split in two smaller triangles, side LN is longer than LP so that means x needs to be a small number. I could either be 2 or 1. Well if you look at the big picture, side LM is longer than LN so it’s gonna need to be bigger. If you say x=1 then you are saying 2(1) +4 = 6 (therefore LM is 6) but if you say x=2 then you are saying 2(2) +4 = 8 which makes more sense


If x=2 then you can use the Pythagorean’s theorem

a2 + b2 = c2
4^2 + b^2 = 5^2
16 + b^2 = 25
25-16= 9
b^2= 9
b= 3


Now that we know what NP is we can do Pythagorean’s theorem to figure out what side LP is (we already know it but you can do it again to check lol)

So the answer is 2
5 0
3 years ago
The base of a solid S is the region bounded by the parabola x^2=8y
nexus9112 [7]

Step-by-step explanation:Updated answer is the second one

8 0
2 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
2 years ago
I need help. Thank you.
Oduvanchick [21]

Answer:

D

A=-5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
You count customers going into the 5 pizza shops in your city. You get 56, 98, 43, 112, and 106. What is the median number of cu
tigry1 [53]

Answer:

Median = 98

Step-by-step explanation:

Organize the numbers in order from least to greatest: 43,56,98,106,112.

Than begin crossing the numbers out

56,98,106

98

8 0
3 years ago
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