Explanation:
Initially, the object is at rest, u = 0
Acceleration of the object,
(a) Distance travel in 2 second can be calculated using second equation of motion as :
(b) Distance travel in 4 second can be calculated using second equation of motion as :
(c) Initial velocity of the object, u = 4 m/s
(d)
Hence, this is the required solution.
Answer:
27.6 m/s
5.64 s
Explanation:
Given:
Δy = 39 m
a = -9.8 m/s²
v = 0 m/s
Find: v₀
v² = v₀² + 2aΔy
(0 m/s)² = v₀² + 2 (-9.8 m/s²) (39 m)
v₀ = 27.6 m/s
Find: 2t
Δy = vt − ½ at²
(39 m) = (0 m/s) t − ½ (-9.8 m/s²) t²
t = 2.82 s
2t = 5.64 s
Answer:
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Explanation: