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Anarel [89]
3 years ago
9

You're the first person to visit Mars and you've just met a group of Martian schoolchildren. They are playing street hockey with

parts from the Mars Polar Lander and, after years of watching Star Trek reruns, they are fluent in English. One of them asks you how your weight and mass have changed since you left Earth. You take a moment to measure both and reply correctly that
(A) your weight is essentially unchanged but your mass is less than on Earth.
(B) your mass is essentially unchanged but your weight is less than on Earth.
(C) your weight and mass have both changed significantly.
(D) neither your weight nor your mass have changed much.
Physics
1 answer:
Liula [17]3 years ago
8 0

Answer: (B) your mass is essentially unchanged but your weight is less than on Earth.

Explanation:

Well, firstly we have to explain the difference between the concepts of mass and weight:

<u>-Mass</u> m is the amount of matter that exists in a body, which only depends on the quantity and type of particles within it. This means mass is an intrinsic property of each body and <u>remains the same regardless of where the body is located.  </u>

<u>-Weight</u> W is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass of the body by the acceleration due gravity g in that place and is mathematically expressed as:  

W=m.g  

So, according to this explanation and since the Earth and Mars have different values ​​of acceleration due gravity (in fact, Mar's g is less than Earth's), <u>your weight has changed, but not your mass.</u>

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3 years ago
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Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
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Answer:

The lowest possible frequency of sound is 971.4 Hz.

Explanation:

Given that,

Distance between  loudspeakers = 2.00 m

Height = 5.50 m

Sound speed = 340 m/s

We need to calculate the distance

Using Pythagorean theorem

AC^2=AB^2+BC^2

AC^2=2.00^2+5.50^2

AC=\sqrt{(2.00^2+5.50^2)}

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Using formula of path difference

\Delta x=AC-BC

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\Delta x=5.85-5.50

\Delta x=0.35\ m

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Using formula of frequency

f=\dfrac{nv}{\Delta x}

Put the value into the formula

f=\dfrac{1\times340}{0.35}

f=971.4\ Hz

Hence, The lowest possible frequency of sound is 971.4 Hz.

8 0
3 years ago
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Found in the nucleus, Has mass of one amu

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An FM radio station transmits a signal with a frequency of 89.1 MHz. Give the wavelength in meters. (use at least three signific
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Answer:

3m

Explanation:

89.1 MHz means

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3.0×10^8meters/second

Wavelength = Speed/Frequency

The wavelength of a

89.1MHz radio signal is

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Please help I’m so confused
Ilya [14]

<em>1.wavelength</em>

<em>2.trough</em>

<em>3.amplitude</em>

<em>4.crest</em>

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