Answer:
a)   E = 1.58 10²¹ J
, b) Oil = 4,236 107 liter
,  e)   T = 54.3 C
Explanation:
a) To calculate the energy that reaches Earth, let us combine that the power emitted by the Sun is distributed uniformly on a spherical surface
      I = P / A
      A = 4π r²
in this case the radius of the sphere is the distance from the Sun to Earth r = 1.5 10¹¹ m
      I = P / A
      I = P / 4π r²
let's calculate
      I = 3,828 10²⁵/4 pi (1.5 10¹¹)²
      I = 1.3539 10²W / m² = 135.4 W / m2
the energy that reaches the disk of the Earth is
     E = I A
the area of a disc
     A = π r²
     E = I π r²
where r is the radius of the Earth 6.37 10⁶ m
      E = 135.4 π(6.37 10⁶)
      E = 1,726 10¹⁶ W
This is the energy per unit of time that reaches Earth
     t = 1 dai (24h / 1day) (3600s / 1h) = 86400 s
      
     E = 1,826 10¹⁶ 86400
      E = 1.58 10²¹ J
b) for this part we can use a direct proportions rule
       Oil = 1.58 10²¹ (1 / 37.3 10⁶)
       Oil = 4,236 10⁷ liter
c) to silence the surface temperature of the Earth we use the Stefan-Bolztman Law
        P = σ A e T⁴
        T = ![\sqrt[4]{P/Ae}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7BP%2FAe%7D) 
nos indicate the refect, therefore the amount of absorbencies
        P_absorbed = 0.7 P
let's calculate
        T = REA (0.7 1.58 1021 / [pi (6.37 106) 2 1)
        T = RER (8,676 106)
        T = 54.3 C
b) Among the other factors that must be taken into account is the greenhouse effect, due to the absorption of gases from the atmosphere