Answer:
The dimension of the plot is 30 yd by 20 yd
Step-by-step explanation:
Given;
Area = 600 yd^2
Length = width + 10
l = w + 10 ......1
Area of a rectangular plot is;
Area A = length × width
A = l × w
Substituting equation 1;
A = (w+10) × w
A = w^2 + 10w
600 = w^2 + 10w
w^2 +10w -600 = 0
Solving the quadratic equation;
w = -30 or 20
cannot be negative
w = 20 yd
l = w+10 = 20+10 = 30yd
The dimension of the plot is 30 yd by 20 yd
Given two numbers x and y such that:
x + y = 12 ... (1)
<span>two numbers will maximize the product g</span>
from equation (1)
y = 12 - x
Using this value of y, we represent xy as
xy = f(x)= x(12 - x)
f(x) = 12x - x^2
Differentiating the above function:
f'(x) = 12 - 2x
Maximum value of f(x) occurs at point for which f'(x) = 0.
Equating f'(x) to 0 we get:
12 - 2x = 0
2x = 12
> x = 12/2 = 6
Substituting this value of x in equation (2):
y = 12 - 6 = 6
Therefore, value of xy is maximum when:
x = 6 and y = 6
The maximum value of xy = 6*6 = 36
The area of the rectangle is A. 6000
Answer:
a. 5
Step-by-step explanation:
To find slope, subtract the y's.
5 - -5 is 10.
Put that on the top of a fraction.
Subtract the x's.
3 - 1 is 2, put that on the bottom of the fraction.
So the slope is 10/2. This simplifies to 5 (because 10÷2 is 5).
The slope is 5.
