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Natali5045456 [20]
4 years ago
7

What would happen to this reaction if an enzyme was added? Mark all that apply.

Chemistry
1 answer:
sergiy2304 [10]4 years ago
4 0
<h3><u>Answer:</u></h3>

The reaction would progress faster and the activation energy would be lowered when the enzyme gets added.

<h3><u>Explanation:</u></h3>

Enzymes are proteins that basically speed up the chemical reaction without being used. Enzymes are usually specific for a particular substrate. The substrate in the reaction bind to the active site of the enzyme which is present on the surface of the enzymes forming the enzyme-substrate complex.

Performing the enzyme-substrate complex the enzyme changes the shape slightly so that the substrate can fit tightly to its active site. Then this enzyme-substrate Complex undergoes a reaction to form a product. Enzymes lower the activation energy of a reaction i.e the required amount of energy needed for a reaction to occur.They do this by binding to a substrate and holding it in a way that allows the reaction to happen more efficiently.

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What is dominium in chemistry? i have it on my worksheet but can't find it on the periodic table or anywhere
Kryger [21]
The answer is complete power to enjoy and dispose of property.
5 0
3 years ago
A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal
bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}

\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}

Solving for V₂ , we get:

<u>V₂ = 45.0 L</u>

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0
4 years ago
(b) Which peak, the one at 365 nm or the one at 435 nm, results from the absorption of
GenaCL600 [577]

Answer:

365nm and Exothermic reaction

Explanation:

b) The Einstein Planck's equation states that

E = hf where E is the energy of a photon

                     h  is the Planck's constant

                     f  is the frequency

But Frequency f = c/λ  where c  is the speed of light

                                                  λ  is the wavelength

Therefore Energy E = hc/λ

From the above equation we see that the Energy of a photon is indirectly proportional to its wavelength

Hence as the wavelength increases from 365nm to 435nm, the energy of the photons decreases

Therefore, a photon will wavelength 365nm would have a higher energy than one will wavelength of 435nm.

c) From the diagram we observe the following:

At high temperatures,   HPR⁺ occurs at a higher concentration than at low temperatures.

At low temperatures, more of PR⁻ is formed than at high temperatures

The equation of the reaction is

HPR⁺ (aq) ⁺ ⇆ H⁺ + PR⁻(aq)      

Le Chartelier's principle states that when an external constraint such as a change in concentration, pressure or temperature is placed on a system in equilibrium, the system acts in such a way as to oppose the change.

Hence a decrease in temperature on the side of reactant, HPR would force the equilibrium to the side of the products, PR in other to accommodate the change

The forward reaction, which produces more of the product PR⁻ is exothermic because  the at low temperatures, the the forward reaction is favoured and equilibrium shifts to the right.

5 0
3 years ago
If i were to put cesium in water and francium in a tub of water which one would explode first?
hoa [83]
Well according to me Cesium releases enough energy that even a small piece blows up in water. Francium is below cesium on the table and would react more readily and violently.
4 0
3 years ago
How many moles of electrons are required for denitrifying organism to reduce 78 moles of nitrate to dinitrogen gas?
enot [183]

Answer:

780 moles e⁻

Explanation:

N⁺⁵ in NO₃⁻ requires 2(5e⁻)  => 1/2 mole N₂(g)

That is, NO₃⁻ + 2(5e⁻/mole N₂ formed) => 1/2N₂

NO₃⁻ + 10e⁻/mole N₂ formed => 1/2N₂

∴ 78 mole NO₃⁻ requires 780 moles e⁻  => 1/2(78) moles N₂ = 39 moles N₂

3 0
3 years ago
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