What is the molarity of a solution prepared by dissolving 54.3 g of Calcium nitrate
1 answer:
Answer: 40 + 2x14 + 6x16 = 164g/mole
54.3g x [1mole / 164g] = 0.331moles
355mL x 1L / 1000mL = 0.355L
molarity = 0.331moles / 0.355L =
00
Explanation:
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