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ollegr [7]
3 years ago
8

Energy transfer by convection is usually restricted to what type of substance? A. Solids only

Chemistry
1 answer:
Lunna [17]3 years ago
4 0

My thought would be B) gases.

I could be wrong but that's what i'd say


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A metal, M, forms an oxide compound with the
lapo4ka [179]

Answer:

Group 1

Explanation: because the compound has a formula of M2O , the number of valence electrons of M should be 1.

5 0
3 years ago
Calculate the mass of carbon dioxide produced from complete combustion of 16.6 g of octane, C8H18, in the following reaction. C8
Oksi-84 [34.3K]

Answer:

51.2g of CO2

Explanation:

The first step is to balance the reaction equation as shown in the solution attached. Without balancing the reaction equation, one can never obtain the correct answer! Then obtain the masses of octane reacted and carbon dioxide produced from the stoichiometric equation. After that, we now compare it with what is given as shown in the image attached.

7 0
3 years ago
Give the half equation to show what happens to oxygen when it is rusting
ycow [4]

Answer:

½O 2 + 2e - + H 2O → 2OH.

Explanation:

Redox reactions - Higher

In terms of electrons:

oxidation is loss of electrons

reduction is gain of electrons

Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:

iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-

oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-

iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-

3 0
3 years ago
How did oxygen first enter Earth's atmosphere?
forsale [732]

Answer:

I think c biological processes

8 0
2 years ago
The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58
Umnica [9.8K]

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

5 0
3 years ago
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