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lutik1710 [3]
3 years ago
14

What is a comet? tell in a short and easy answer​

Chemistry
1 answer:
Ede4ka [16]3 years ago
5 0
A comet is a small icy, small Solar System body
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Which of the following are forms that chemical hazards can be in?
BabaBlast [244]
Fire, explosions, acid, fumes-take your pick here.
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3 years ago
What has its own size and shape
erma4kov [3.2K]
I guess it is gases
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8 0
3 years ago
State the oxidation number assigned to each bold element in the formula: NH4+1 a 3 b -3 c -1 d 6
Leya [2.2K]
The fomula is NH4 (1+)


There are only two elements N and H.


As per oxidation state rules, the most electronegative element will have a negative oxidation state and the other element will have a positive oxidation state.


N is more electronative than H, so H will have a positive oxidation state and nitrogen will have a negative oxidation state.


You can also use the rule that states the hydrogen mostly has 1+ oxidation state,except when it is bonded to metals.


In conclusion the oxidation state of H in NH4 (1+) is 1+.


Now you must know that the sum of the oxidations states equals the charge of the ion, which in this case is 1+.


That implies that 4* (1+)  + x =   1+


=> x = (1+) - 4(+) = 3-


Answer:  the oxidation state of N is 3-, that is the option b.
8 0
3 years ago
The following equation represents the type of reaction called
Eva8 [605]

Answer: C REDUCTION

Explanation:

Guessed after knowing oxidation isn't the answer. Got right

7 0
3 years ago
Select the compound that is most likely to increase the solubility of ZnSe when added to water.NaCnMgBr2NaClKClO4
vlada-n [284]

Answer:

NaCl.

Explanation:

In the solution, ZnSe ionizes to Zn^2^+ and Se^2^- . Following reaction represents the ionization of ZnSe in solution -

ZnSe ⇄ Zn^2^+ + Se^2^-

As we want to increase the solubility of ZnSe, we must decrease the concentration of dissociated ions so that the reaction continues to forward direction.

If we add NaCl to this solution, then we have Na^+ and Cl^- in the solution which will be formed by the ionization of NaCl.

Now, Zn^2^+ in the solution will react with two Cl^- ions to form ZnCl_2 as follows -

Zn^2^++2Cl^- ⇄ ZnCl_2

Due to this reaction the concentration of Zn^2^+ will decrease in the solution and more ZnSe can be soluble in the solution.

6 0
2 years ago
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