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Ghella [55]
3 years ago
6

Which phrase correctly describes the particles that make up water vapor?

Chemistry
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

i believe its A but im not sure

its the only one that makes any sense

plz mark  brainliest

\

Explanation:

You might be interested in
opper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f =
Y_Kistochka [10]

Answer:

55.373g/l

Explanation:

The dissolved amount of sparingly soluble salts is interlinked with a unitlesss quantity called as solubility product. It is a fixed quantity that only increases with the rise in temperatures and is used to predict the salting out of compounds. If the value of ionic product (Q) is larger than (Ksp), precipitation of compound occurs.

Given:

The solubility product of CuBr is 6.3×10−9.

The concentration of NH3 is 0.10 M.

Formula and Calculations:

The dissolution reaction (I) of CuBr is shown below.

The reaction showing dissolution of CuBr in NH3 is shown below.

The above reaction can be obtained by adding reaction (I) and (II) as shown below.

The equilibrium constants will get multiplied.

Suppose the solubility of CuBr is “s”.

It is given that concentration of NH3 is 0.10 M.

The equilibrium constant expression for the above reaction is as follows,

Here,

The concentration of pure solids is 1 M. Thus, the concentration of CuBr is 1 M.

As calculated, the value of Ksp is 396.9.

Substitute all the required values in above formula.  

On further solving above equation,

Therefore, the solubility of CuBr in ammonia is 0.386 M.

The formula to calculate solubility

Solubuility (g/l)= Molarity(M) x Molarmass

Chemistry homework question answer, step 2, image 10

The molar mass of CuBr is 143.45 g/mol.

The formula to calculate solubility in g/L is given below.

The molar mass of CuBr is 143.45 g/mol.

therefore,

solubility = 0.386M x 143.45g/mol

where (M = mol/l)

solubility = 55.375g/l

5 0
3 years ago
Please help meee 1st question​
spayn [35]
360 seconds?

i’m guessing that is the answer as the question is unreasonable
5 0
3 years ago
At a certain temperature the vapor pressure of pure methanol is measured to be . Suppose a solution is prepared by mixing of met
CaHeK987 [17]

Answer:

Partial pressure is 0.13 atm

Explanation:

CHECK THE COMPLETE QUESTION BELOW :

At a certain temperature, the vapor pressure of pure methanol is measured to be 0.43atm. Suppose a solution is prepared by mixing 88.2 g of methanol and 116.g of water. Calculate the partial pressure of methanol vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal.

Using Raoult´s law for ideal soultions we have

P(A) = X(A) *Pº(A)

where P(A) is the partial vapor pressure pressure of methanol,

X(A) is the mole fraction of solute (methanol) in solution,

Pº(A) is the vapor pressure of pure solute

Raoult's law states that the vapor pressure of a solution is dependent on the mole fraction of a solute added to the solution.

Raoult's law can be expressed below

Psolution = ΧsolventP0solvent.

Expressing it interns of the constituents given in the question we have

P(CH₃OH) = X(CH₃OH) x Pº(CH₃OH)

To calculate the mole fraction of CH₃OH, we make use of the formula below :

X(A) = mol (A) / ntotal

Ntotal = (sum of number of moles of A )+( moles solvent)

mol (CH₃3OH) can be calculated as :: 88.2 g/ 32 g/mol = 2.76 mol of CH₃OH

mol (H₂O) can be calculated as ::116 g/ 18 g/mol = 6.44 mol

total n = (6.44 + 2.76) mol = 9.20 mol

To calculate the partial pressure the we say;

P(CH₃OH) = (2.76 mol CH + 9.20 mol) x( 0.43 atm) = 0.13 atm

Hence, the partial pressure rounded to two significant figures is 0.13 atm

8 0
3 years ago
Problem: If you push an object with a constant force of 100 N over a 10-meter distance. How much energy transfer occurs on the o
Sveta_85 [38]

The energy transferred on the object is 1000 Joules.

Given:

An object on which a constant force of 100 N was applied to displace it over a distance of 10 meters.

To find:

The energy transfer occurs on the object.

Solution

The force applied on the object = F = 100 N

The displacement of the object = d = 10 m

The energy transferred on the object or work done is given by:

W = F\times d\\W=100 N\times 10 m = 1,000 J

The energy transferred on the object is 1000 Joules.

Learn more about work done here:

brainly.com/question/8119756?referrer=searchResults

brainly.com/question/3951672?referrer=searchResults

8 0
3 years ago
A solution contains 15 grams of salt per litter of solution. How many grams of salt are in 3.3 litters of solution?​
Verizon [17]

49.5g

Explanation:

Mass of salt = 15g

Volume of solution = 1L

Volume of given solution = 3.3L

Unknown:

Mass of salt in the solution = ?

Solution:

Since we have been given the concentration of the salt in the solution, we can use it to solve the problem.

Concentration; 15g/L

Given;

    In 1L of the solution we have 15g of salt,

In    3.3L of the solution we will have 3.3 x 15 = 49.5g

The salt is the solute and it represents the dissolved substances.

learn more:

Concentration brainly.com/question/4641902

#learnwithBrainly

7 0
3 years ago
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