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Lady_Fox [76]
3 years ago
7

Please help. Its for chemistry

Chemistry
2 answers:
Llana [10]3 years ago
5 0

Answer: 3rd one

Explanation:

Katen [24]3 years ago
3 0
Decrease!!
I’m pretty sure












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Which method involves separating a solution by liquids moving across a selectively permeable membrane?
Kisachek [45]

Answer:

OSMOSIS

Explanation:

Osmosis (/ɒzˈmoʊ.sɪs/) is the spontaneous net movement or diffusion of solvent molecules through a selectively permeable membrane from a region of high water potential (region of lower solute concentration) to a region of low water potential (region of higher solute concentration),

7 0
3 years ago
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In the original mixtures, test tube 1 contained magnesium and a zinc compound, and test tube 2 contained zinc
FromTheMoon [43]

Answer:

Test tube one is a compound because it is 2 elements combine..Test tube to is an element

Explanation:

5 0
3 years ago
Five gases combined in a gas cylinder have the following partial pressures: 3.00 atm (N2), 1.80 atm (O2), 0.29 atm (Ar), 0.18 at
levacccp [35]
In order to solve the total pressure that is exerted by the gases, we need to use the Dalton's Law of Partial pressures. These are the calculations that you need to find out the total amount of pressure exerted to the gases:

3.00atm (N2) + 1.80atm (O2) + 0.29atm (Ar) + 0.18atm (He) + 0.10atm (H),
add up all of that, and the answer would turn out to be: 5.37atm.
8 0
3 years ago
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How much heat energy is required to raise the temperature of 0.368 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of co
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23.0 + 60.0 = 83.0° C heat energy is required to raise
7 0
3 years ago
Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
ad-work [718]

Initial volume of the balloon = V_{1}= 348 mL

Initial temperature of the balloon T_{1} = 25.0^{0}C + 273 = 298 K

Final volume of the balloon V_{2} = 322 mL

Final temperature of the balloon = T_{2} = ?

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

On plugging in the values,

\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }

T_{2} =276 K

Therefore, the temperature of the freezer is 276 K

5 0
3 years ago
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