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Korvikt [17]
2 years ago
12

Can someone help please!!!!​

Chemistry
1 answer:
Valentin [98]2 years ago
8 0

2. 5 acids: coffee, lemonade, soda pop, orange juice, vinegar

5bases: ammonia, baking soda, cough medicine, liquid soaps

3. Acids are very common in some of the foods we eat.

Bases have properties that mostly contrast with those acids

4. Acid+Base=H2O+Salt

HCI+NaOH=H2O+NaCI

Explanation:

2. (all those acids are strong (in pH meaning those are weak and don't affect you) (most the bases are very strong like ammonia)

4. Salt means any ionic compound formed from an acid/base reaction

Hope this helped

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Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
2 years ago
A chemist wishes to mix a solution that is 12​% acid. She has on hand 14 liters of a 6​% acid solution and wishes to add some 16
Maslowich

Answer:

25 liters of the 16% solution should be added.

Step by Step Explanation:

pure acid amount + pure acid amount = total pure acid amount

So,

0.02*10 + 0.16*x = 0.12*(10+x)    

0.02*10 + 0.16x = 0.12*10 + 0.12*x

0.16*x - 0.12*x = 0.12*10 - 0.02*10

(0.16 - 0.12)*x = 0.12*10 - 0.02*10

x = (0.12*10-0.02*10)/(0.16-0.12)=25

Check:   (0.2*10+0.16*25)/(10+25) = 0.12 = 12% of concentration of the final mixture.   ! Correct !

3 0
3 years ago
Given the following equation: 2C6H6 + 1502 - 12CO2 + 6H20
Margarita [4]

Answer:

a) 30 moles

Explanation:

                           2C6H6 + 1502 -------> 12CO2 + 6H20

from reaction      2 mol       15 mol

given                    4.0 mol     x mol

x = 4.0*15/2 = 30. mol

5 0
2 years ago
Someone help out plz?
Fiesta28 [93]
The temperatures increased
7 0
2 years ago
How does ph affect enzyme-catalyzed reactions?
Ilya [14]
Changes in pH may not only affect the shape of an enzyme but it may also change the shape or charge properties of the substrate so that either the substrate connot bind to the active site or it cannot undergo catalysis. In geneal enzyme have a pHoptimum. However the optimum is not the same for each enzyme
4 0
3 years ago
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