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Artemon [7]
4 years ago
13

An object moves uniformly around a circular path of radius 23.5 cm, making one complete revolution every 1.95 s. (a) What is the

translational speed of the object? (b) What is the frequency of motion in hertz? (c) What is the angular speed of the object?
Physics
1 answer:
uranmaximum [27]4 years ago
6 0

Explanation:

a)

The circumference of the path is:

C = 2πr

C = 2π (0.235 m)

C = 1.48 m

Velocity = displacement / time

v = 1.48 m / 1.95 s

v = 0.757 m/s

b)

1 rev / 1.95 s = 0.513 Hz

c)

1 rev / 1.95 s × (2π rad / rev) = 3.22 rad/s

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A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit
likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density \mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 120=753.6rad/sec

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt

From the relation we can see that power P\ \propto\ A^2

So if amplitude is halved then power will be \frac{1}{4} times

So power will be equal to \frac{0.2023}{2}=0.0505watt

4 0
3 years ago
You buy a 75 watt light bulb. the label means that
alukav5142 [94]
The label means that the bulb will consume 75 joules of electrical energy in 1 sec
4 0
4 years ago
Lizard: A lizard is running in a straight line according to the following: xx(tt) = tt3⁄3 − tt2 + tt He starts at tt = 0. (a) De
insens350 [35]

Answer:

Explanation:

a ) x ( t ) = t³ / 3 - t² + t

v = dx / dt = 3 t² / 3 - 2 t + 1 = t² -  2 t + 1

b ) lizard is at rest , v( t ) = 0

t² -  2 t + 1  = 0

( t - 1 )² = 0

t = 1

c )

velocity is positive when

t² -  2 t + 1  > 0

( t - 1 ) ² > 0

Here we see that LHS is a square so it is always positive whatever be the value of t

So velocity is always positive or lizard is always moving in positive x direction .

d ) It never moves in negative x direction .

e )

a ( t ) = dv / dt = 2t - 2

t = 1

so it has zero acceleration at t = 0 .

7 0
3 years ago
Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and ex
Ahat [919]

The question is incomplete. The complete question is :

Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.

What is the frequency of the sound?

Solution :

Given :

The distance between the two loud speakers, d = 1.8 \ m

The speaker are in phase and so the path difference is zero constructive interference occurs.

At the point D, the speakers are out of phase and so the path difference is $=\frac{\lambda}{2}$

Therefore,

$AD-BD = \frac{\lambda}{2}

$\sqrt{(1.8)^2+(3)^2-3} =\frac{\lambda}{2}$

$\lambda = 2 \times 0.4985$

$\lambda = 0.99714 \ m$

Thus the frequency is :

$f=\frac{v}{\lambda}$

$f=\frac{340}{0.99714}$

f=340.9744 Hz

3 0
3 years ago
On planet X, an object weighs 7.04 N. Onplanet B where the magnitude of the free-fallacceleration is 1.91g(whereg= 9.8 m/s2isthe
timurjin [86]
<h2>Mass of object in Earth is 1.37 kg</h2>

Explanation:

On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.

We have

           Weight = Mass x Acceleration due to gravity

On planet B

           25.74 = Mass x 1.91 g

           25.74 = Mass x 1.91 x 9.81

           Mass = 1.37 kg

Mass is constant for an object. It will not change with location.

Mass of object in Earth = Mass of object in Planet B

Mass of object in Earth = 1.37 kg

4 0
3 years ago
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