Answer:
so height is 0.1283 m
Explanation:
given data
height = 28 cm
diameter = 11 cm
cross-sectional area = 1.55 cm2
water flow rate = 2.46×10^−4 m3/s
to find out
How high will the water in the bucket rise
solution
we know that here
potential energy = kinetic energy
mgh = 1/2 mv²
multiply both sides by the 2 and we get
2mgh=mv²
solve it we get
√(2gh) = v ....................1
h = v²/2g ...............2
and
flow rate = A V
2.46×10^−4 = V 1.55×10^−4
V = 1.5870 m/s
so from 2
h = v²/2g
h = 1.5870²/ 2(9.81)
h = 0.1283 m
so height is 0.1283 m
Answer: It is B 38% have a good day :DDD
Answer:
38 is a good girl and a great place to work for u and I miss you y and I miss you much love your love and love to
Answer: Given: h₀=5cm
p=30cm
hi
f=45cm
require: q=?
hi=?
formulas:
1/f=1/p+1/q
hi/h₀=q/p
calculations:1/q=1/f-1/p
1/q=1/45-1/30
1/q=0.022=0.033
1/q= = -0.011
q=1/-0.011
q= -90.91cm
hi=p × h₀/q
hi=30ₓ5/-90.91
hi=150/-90.91
hi= -1.65cm
image is virtual , erect and diminished
please mark as brainliest plzzzzzzzzzz
