Professional Application: A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 11 0,000 kg of scrap metal into it. (a) What is the final velocity of the loaded freight car?
1 answer:
Answer:
0.182 m/s
Explanation:
m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s
let the velocity of loaded freight car is v
Use the conservation of momentum
m1 x u1 + m2 x 0 = (m1 + m2) x v
30,000 x 0.85 = (30,000 + 110,000) x v
v = 0.182 m/s
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Hope this helps you!!!!
Answer:
V 2 = 1.33m/s
Explanation:
M1 = 30 ton
M2 = 90 ton
V1 = 4 m/s
V2 = ?
Assumption: momentum conserved, no friction
initial momentum = final momentum = 0
momentum : p = MV
(M1*V1) - (M2*V2) = 0
V2 = (30*4)/90 = 1.33m/s
Answer:
78.6m/s
Explanation:
We know that frictional force also contributes to the centripetal force that keeps the car in circular motion in the turn
And is given as
F= mv²/r
But the frictional force is
F= ugm
= = 0.7*1200*9.8= 8232N
To find maximum velocity v we say
V= √F x r/m
= √ 8232* 90 /1200
= 78.6m/s
2. Yes it is independent of mass of car
