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aleksandr82 [10.1K]
4 years ago
6

Professional Application: A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 11

0,000 kg of scrap metal into it. (a) What is the final velocity of the loaded freight car?
Physics
1 answer:
Nataliya [291]4 years ago
5 0

Answer:

0.182 m/s

Explanation:

m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s

let the velocity of loaded freight car is v

Use the conservation of momentum

m1 x u1 + m2 x 0 = (m1 + m2) x v

30,000 x 0.85 = (30,000 + 110,000) x v

v = 0.182 m/s

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(Please Help, Will Give BRAINLIEST Answer)
Xelga [282]

Answer:

A

Explanation:

Initial gravitational energy = final kinetic energy + heat

mgh = KE + Q

(50 kg) (9.81 m/s²) h = 78400 J + 884000 J

h = 1960 meters

4 0
3 years ago
Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide
velikii [3]

Answer:

  k_max = 31.82 w/mk

  k_min  = 17.70 w/mk

Explanation:

a) the maximum thermal conductivity is given as

k_{max} = k_m*v_m + k_p*v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

            = 66*0.17 + 28*0.83

           k_max = 31.82 w/mk

b) the minimum thermal conductivity is given as

k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}

          = \frac{28+66}{28*0.17 +66*0.83}

       k_min  = 17.70 w/mk

7 0
3 years ago
All these are properties except
marin [14]
Amethyst... because it's silicon dioxide
3 0
3 years ago
ANSWER ASAP PLS!!!
kodGreya [7K]

Answer:

A solenoid field is increased with the increase in the current flow through the coil.

Explanation:

A solenoid is a current carrying coil with a significant number of loops. It works like an electromagnet inside which, a uniform and strong magnetic field is created. The magnetic field outside the solenoid field is nearly zero but not exactly zero.

While experimenting with the solenoid, scientists came to know that the magnetic field generated by the solenoid increases with the increase in the current, flowing through the solenoid.

The magnetic field works strongly around the arena of coil. The field changes its direction only near the ends and gets weak. Else its uniform throughout the loops.

The magnetic field inside the solenoid can be formulated as,

B=\mu n I

Where,

B = Magnetic field generated by the solenoid

\mu = Constant

I = Current flowing through the loops of the solenoid

5 0
3 years ago
a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m f
goblinko [34]

The effort applied : 200 N

<h3>Further explanation</h3>

Equilibrium rotation

\large {\boxed {\bold {\sum \tau = 0}}

F₁.d₁-F₂.d₂=0

F₁.d₁=F₂.d₂

F₁=500 N

d₁=0.5 m

d₂=1.75-0.5=1.25 m

\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N

5 0
3 years ago
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