Question

Does anybody know how to determine the angle again? of Q.B

Answer 1

Answer:

Therefore the measur angle ACB

$m\angle ACB=61.93\°$

Step-by-step explanation:

Given:

ΔABC is a right Triangle at ∠A = 90°

AB = 15    ....Side Opposite to ∠ACB

AC = 8     ....Side Adjacent to ∠ACB

To Find:

m∠ACB = ?

Solution:

In Right Angle Triangle ABC, Tangent Identity we have

$\tan (\angle ACB) = \dfrac{\textrm{side opposite to angle ACB}}{\textrm{side adjacent to angle ACB}}$

Substituting the values we get

$\tan (\angle ACB) = \dfrac{AB}{AC}=\dfrac{15}{8}=1.875\\\\\angle ACB=\tan^{-1}(1.875)\\m\angle ACB=61.93\°$

Therefore the measur angle ACB

$m\angle ACB=61.93\°$