The answer is: " -21 " .
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We are asked to solve for: "6t" ; which is: "6 * t" .
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Given: 3t − 7 = 5t ; Solve for "t" ; then solve for "6t" ;
3t − 7 = 5t ; Subtract "3t" from each side of the equation;
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3t − 7 − 3t = 5t − 3t ;
to get: -7 = 2t ;
Divide EACH side of the equation by "2" ; to isolate "t" on one side of the equation; and to solve for "t" ;
-7/2 = 2t / 2 ;
-3.5 = t ; ↔ t = - 3.5 ;
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Now, solve for "6t" ;
6 t = 6*(-3.5) = - 21 . The answer is: " -21 " .
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Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
