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seropon [69]
3 years ago
13

A student is doing a lab experiment in which she uses diffraction to measure the width of a shaft of her hair. She shines a 530

nm green laser pointer on a single hair, which produces a diffraction pattern on a screen 1.2 m away. The width of the central maximum of the pattern is 14 mm. a. What is the thickness of the hair? (91µm) b. If she chose a wider shaft of hair, how would this change the width of the central maximum? (b): For a single slit, we know that a wider slit gives a narrower pattern; the same is true for the hair.
Physics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

.09 mm

Explanation:

In case of diffraction by single slit with width a the width of central maxima is given below

width = 2 λD/a

where λ is wavelength of light , D is distance of screen , a is width o slit

substituting the given values

14 x 10⁻³ = \frac{2\times530\times10^{-9}\times1.2}{a}

a = .09 mm

b) If a is greater , width of central maxima will be less wide.

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Air as an ideal gas enters a diffuser operating at steady state at 5 bar, 280 K with a velocity of 510 m/s. The exit velocity is
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0=(h_1-h_2)+\frac{(v_1^2-v_2^2)}{2}     ------ equation(1)

we can rewrite the above equation as :

0 = c_p(T_1-T_2)+ \frac{(v_1^2-v_2^2)}{2}

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T_2= 280+\frac{((510)^2-(120)^2)}{2(1.004)} *\frac{1}{10^3}

T_2 = 402.36 \ K

Thus, the exit temperature = 402.36 K

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P_2=P_1(\frac{T_2}{T_1})^\frac{k}{k-1}

P_2 = 5 (\frac{402.36}{280} )^\frac{1.4}{1.4-1}

P_2 = 17.79 \ bar

Therefore, the exit pressure is 17.79 bar

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