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seropon [69]
3 years ago
13

A student is doing a lab experiment in which she uses diffraction to measure the width of a shaft of her hair. She shines a 530

nm green laser pointer on a single hair, which produces a diffraction pattern on a screen 1.2 m away. The width of the central maximum of the pattern is 14 mm. a. What is the thickness of the hair? (91µm) b. If she chose a wider shaft of hair, how would this change the width of the central maximum? (b): For a single slit, we know that a wider slit gives a narrower pattern; the same is true for the hair.
Physics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

.09 mm

Explanation:

In case of diffraction by single slit with width a the width of central maxima is given below

width = 2 λD/a

where λ is wavelength of light , D is distance of screen , a is width o slit

substituting the given values

14 x 10⁻³ = \frac{2\times530\times10^{-9}\times1.2}{a}

a = .09 mm

b) If a is greater , width of central maxima will be less wide.

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distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.
a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s

So, the speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

4 0
2 years ago
"what is the period of one vibration of this tone?"
Viktor [21]
The full question is:
On a keyboard, you strike middle C, whose frequency is 256 Hz. What is the period of one vibration of this tone?
The period of a vibration is the time it takes for the particle to make one full oscillation. Frequency is by definition number of full oscillations per unit of time.
When the frequency is expressed in Hz that unit of time is one second.
So there is the following relation between frequency and period:
T=\frac{1}{f}
When we plug in the numbers we get:
T=\frac{1}{256}=0.0039$s
7 0
2 years ago
Assuming things about someone based on your experiences with similar people you have encountered is called
AysviL [449]

Answer:

presumptuous

Explanation:

it's what you call someone who assumes something

3 0
2 years ago
What is the Galaxy we live in called?
Fittoniya [83]
The Milky Way is a spiral galaxy type so it has arms sort of like an octopus. We live in the Milky Way
7 0
2 years ago
Read 2 more answers
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Galina-37 [17]

Answer: 2 seconds

Explanation:

Given that,

Time (T) = ?

Charge (Q) = 4 coulombs

current (I) = 2 Amps

Since charge depends on the amount of current flowing through the wire in a given time, hence

Charge = Current x Time

Q = IT

4 coulombs = 2 Amps x Time

Time = 4 coulombs / 2 Amps

Time = 2 seconds

Thus, it takes 2 seconds for the current to flow through the wire

4 0
3 years ago
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