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Serjik [45]
2 years ago
14

Velocity and acceleration are both vectors; they have a

Physics
1 answer:
pickupchik [31]2 years ago
7 0

ITS ABOUT DRIVE

ITS ABOUT POWER

WE STAY HUNGRY

WE DEVOUR

PUT IN THE WORK

PUT IN THE HOURS ⌚

AND TAKE WHATS OURS

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Which statement accurately describes the charge of the nucleus of an atom?
Aleksandr [31]

Answer:

A. The nucleus can be either positively charged or neutral.

Explanation:

The nucleus of an atom contains protons and neutrons only. Whereas electrons revolve around the nucleus. Protons are positively charged, neutrons have no charge and electrons are negatively charged.

3 0
3 years ago
How much energy, in Joules, is needed to raise the temperature from 25.87°C to 33.16°C in a 2.66 kg block of each of the followi
RUDIKE [14]

Answer:

(a) Silver, H = 455.67 J

(b) Iron, H = 870.67 J

(c) titanium, H = 1012.23 J

Explanation:

mass of block, m = 2.66 kg = 266 g

T1 = 25.87° C

T2 = 33.16° C

ΔT = T2 - T1 = 33.16 - 25.87 = 7.29° C

(a) Specific heat of silver, c = 0.235 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.235 x 7.29 = 455.67 J

(b) Specific heat of iron, c = 0.449 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.449 x 7.29 = 870.67 J

(c) Specific heat of titanium, c = 0.522 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.522 x 7.29 = 1012.23 J

6 0
3 years ago
What is newtons first law of motion​
Brums [2.3K]
An object in motion will remain in motion unless an outside force stops is.
6 0
3 years ago
A 25.0 kg object is held 8.50 m above the ground. Calculate its PE
pantera1 [17]

Answer:=mgh

Explanation:

6 0
2 years ago
In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-1
BaLLatris [955]

Answer:

Number of electrons, n = 6

Explanation:

Total charge in a single droplet, q=-9.6\times 10^{-19}\ C

The measured charge of any single droplet, e=-1.6\times 10^{-19}\ C

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

q=ne

n=\dfrac{q}{e}

n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.

7 0
3 years ago
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