How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? cacl2(aq) + k2co3(aq) → 2 kcl(aq) + caco3
(aq) 1.12 g 2.23 g 0.896 g 4.47 g?
2 answers:
The calcium chloride needed to produce 1.5 grams of KCl is: 1.12 grams
<h3><em>Further explanation</em></h3>Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
Reactions that occur:
CaCl₂ (aq) + K₂CO₃ (aq) → 2 KCl (aq) + CaCO₃ (aq)
From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products
mol CaCl₂: moles of KCl = 1: 2
relative molecular mass KCl = 74.6
relative molecular mass of CaCl2 = 111
then the mole:
mole KCl = mass: relative molecular mass
mole KCl = 1.5 gram: 74.6
mole KCl = 0.020107
so that
mole CaCl₂ = 1/2. 0.020107
mole CaCl₂ = 0.0100535
So the mass of CaCl2 = mole x relative molecular mass
mass CaCl₂ = 0.0100535 x 111
mass CaCl₂ = 1.12 gram
<h3><em>Learn more</em></h3>moles of water
grams of oxygen required
mass of copper required
Keywords: CaCl2, KCl, mole, mass, relative molecular mass
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Answer:
3.38%
Explanation:
Given that;
the mass of the whole milk sample = 100 g
volume of HCl = 100 mL = 0.1 L
molarity of HCl = 0.5 M
volume of NaOH = 34.50 mL = 0.0345 L
molarity of NaOH = 0.3512 M
Since we knew the molarity and volume of both HCl and NaOH; we can calculate their corresponding number of moles present.
So, number of moles of HCl = molarity of HCl × volume of HCl
number of moles of HCl = 0.5 M × 0.100 mL
= 0.05 mole
number of moles of NaOH = Molarity of NaOH × Volume of NaOH
number of moles of NaOH = 0.3512 M × 0.0345 L
= 0.012 mole
From the question, we can deduce that the number of HCl that is consumed by NH₃ is equal to the number of moles of HCl that is consumed by NaOH.
SO, number of moles of HCl consumed by NH₃ = Total moles of HCl - moles of HCl consumed by NaOH
= 0.05 mole - 0.012 mole
= 0.038 mole
However, to determine the mole of NH₃ present , we have:
number of moles of NH₃ present = number of moles of HCl consumed by NH₃ = 0.038
∴ the mass of Nitrogen with the molecular weight (14.0 g/mol) = 0.038 moles × 14.0 g/mol
= 0.530 g
Now, the percentage of Nitrogen can be calculated as;
%
the percentage of protein in the sample = CP × %age of N
where CP is given as 6.38
∴ the percentage of protein in the sample = 6.38 × 0.530%
the percentage of protein in the sample = 3.3814%
the percentage of protein in the sample = 3.38%