How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? cacl2(aq) + k2co3(aq) → 2 kcl(aq) + caco3
(aq) 1.12 g 2.23 g 0.896 g 4.47 g?
2 answers:
The calcium chloride needed to produce 1.5 grams of KCl is: 1.12 grams
<h3><em>Further explanation</em></h3>Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
Reactions that occur:
CaCl₂ (aq) + K₂CO₃ (aq) → 2 KCl (aq) + CaCO₃ (aq)
From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products
mol CaCl₂: moles of KCl = 1: 2
relative molecular mass KCl = 74.6
relative molecular mass of CaCl2 = 111
then the mole:
mole KCl = mass: relative molecular mass
mole KCl = 1.5 gram: 74.6
mole KCl = 0.020107
so that
mole CaCl₂ = 1/2. 0.020107
mole CaCl₂ = 0.0100535
So the mass of CaCl2 = mole x relative molecular mass
mass CaCl₂ = 0.0100535 x 111
mass CaCl₂ = 1.12 gram
<h3><em>Learn more</em></h3>moles of water
grams of oxygen required
mass of copper required
Keywords: CaCl2, KCl, mole, mass, relative molecular mass
You might be interested in