Calculate the number of grams of 02, produced when 43 grams of potassium chlorate decomposes.
1 answer:
Mass O2 = = 16.832 g
<h3>Further explanation</h3>
Given
43 grams of potassium chlorate
Required
Mass of O2
Solution
Reaction
2KClO3 ⇒3O2 + 2KCl
Mol KClO3 :
= mass : MW
= 43 g : 122,55 g/mol
= 0.3509
From the equation, mol O2 :
= 3/2 x moles KClO3
= 3/2 x 0.3509
= 0.526
Mass O2 :
= 0.526 x 32 g/mol
= 16.832 g
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