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RUDIKE [14]
3 years ago
14

they ordered 3sodas for 11.25. Jason ordered one cheeseburger and one soda for $5 how much dose one cheeseburger cost ​

Mathematics
1 answer:
drek231 [11]3 years ago
8 0

Answer:

1.25

Step-by-step explanation:

11.25/3     5-3.75= 1.25

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ZA and ZB are vertical angles. If m A = (8x – 20)° and m B = (3x – 5)º,
kobusy [5.1K]

Answer:

x=11

Step-by-step explanation:

Vertical angles are congruent, so m∠A = m∠B.

4x+8 = 5x-3

Subtract 5x from both sides.

-1x+8=-3

Subtract 8 from both sides to isolate the variable.

-1x=-11

Divide both sides by -1 to solve for x.

x=11

Plug in 11 for x into m∠A=(4x+8)=(4(11)+8)=(44+8)=52.

4 0
3 years ago
A 50 foot rope weighing a total of 32 lbs extended over a cliff that is 35 feet to the ground. A large 8 pound bucket with 19 ga
larisa86 [58]

Answer:

A function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is W=16(50-x)+(19-\frac{x}{5})(8.3)x and  the work to get the bucket to the top of the cliff is 3726 foot-lbs

Step-by-step explanation:

Work done to lift the rope by distance x feet:

W_1=32(\frac{50-x}{2})

Work done to lift the bucket by distance x feet:

W_2=(19-\frac{x}{5})(8.3)x

On reaching top 7 gallons of water spilled out so , on going up by x feet \frac{7x}{35}=\frac{x}{5} gallons of water spilled out.

a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground:

W=16(50-x)+(19-\frac{x}{5})(8.3)x

Now the work to get the bucket to the top of the cliff i.e. x =35

W=16(50-35)+(19-\frac{35}{5})(8.3)(35)

W=3726

Hence, a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is W=16(50-x)+(19-\frac{x}{5})(8.3)x and  the work to get the bucket to the top of the cliff is 3726 foot-lbs

5 0
2 years ago
The amount y (in grams) of the radioactive isotope fermium-253 remaining after t hours is y=a(0.5)t/72, where a is the initial a
almond37 [142]

Answer:

Per hour decay of the isotope is 0.96%.

Step-by-step explanation:

Amount of radioactive element remaining after t hours is represented by

y=a(0.5)^{\frac{t}{72}}

where a = initial amount

t = duration of decay (in hours)

Amount remaining after 1 hour will be,

y=a(0.5)^{\frac{1}{72} }

y = 0.9904a

So amount of decay in one hour = a - 0.9904a

                                                      = 0.0096a gms

Percentage decay every hour = \frac{\text{Amount of decay}}{\text{Initial amount}}\times 100

                                                  = \frac{0.0096a}{a}\times 100

                                                  = 0.958 %

                                                  ≈ 0.96 %

Therefore, per hour decay of the radioactive isotope is 0.96%.

7 0
3 years ago
Functions can be defined using graphs, tables, and ordered pairs. What is the domain of a function?
Agata [3.3K]

Step-by-step explanation:

the domain is all numbers

5 0
3 years ago
You roll a fair 6 sided dice. What is p(not 5)?
liq [111]

Answer:

p(not 5) = 5/6

Step-by-step explanation:

The probability that we roll a 5 is 1/6. So, the probability we don't roll a five is simple 1 minus that:

1-\frac{1}{6} = \frac{5}{6}

And that's your answer.

7 0
3 years ago
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