Answer:
16.6 mg
Explanation:
Step 1: Calculate the rate constant (k) for Iodine-131 decay
We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.
k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹
Step 2: Calculate the mass of iodine after 8.52 days
Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.
ln I = ln I₀ - k × t
ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day
I = 16.6 mg
Answer:
Explanation:
1. Calculate the rate constant
The integrated rate law for first order decay is
where
A₀ and A_t are the amounts at t = 0 and t
k is the rate constant
2. Calculate the half-life
Ag - 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d⁹
Answer:
a kind of radiation including visible light, radio waves, gamma rays, and X-rays, in which electric and magnetic fields vary simultaneously.
Answer:
Pb (NO₃)₂(aq) + 2KCl(aq) → 2KNO₃(aq) + PbCl₂(s)
Explanation:
In given chemical equation the aqueous lead (II) nitrate react with aqueous potassium chloride and form aqueous potassium nitrate and lead chloride.
Chemical equation:
Pb (NO₃)₂(aq) + KCl(aq) → KNO₃(aq) + PbCl₂(s)
Balanced chemical equation:
Pb (NO₃)₂(aq) + 2KCl(aq) → 2KNO₃(aq) + PbCl₂(s)
ionic equation:
Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺(aq) + 2Cl⁻ (aq) → 2NO₃⁻(aq) + 2K⁺(aq) + PbCl₂(s)
Net ionic equation:
Pb²⁺ (aq) + 2Cl⁻ (aq) → PbCl₂(s)
The NO₃⁻(aq) and K⁺(aq) are spectator ions that's why these are not written in net ionic equation. The PbCl₂ can not be splitted into ions because it is present in solid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
