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Juli2301 [7.4K]
3 years ago
8

Which statement about atmospheric pressure near Earth’s surface is true?

Chemistry
2 answers:
valentinak56 [21]3 years ago
6 0
I think the correct answer from the choices listed above is option B. The statement that is true about the atmospheric pressure near Earth’s surface would be that it decreases as you move away from Earth’s surface. P<span>ressure decreases with increasing altitude. Hope this answers the question.</span>
Dominik [7]3 years ago
6 0

Answer : Option B) It decreases as someone moves away from earth's surface.

Explanation : The atmospheric pressure at the surface of the earth is at maximum, it is seen that as we move away from the surface of the earth the pressure decreases. As on the top of mountains the atmospheric pressure is found to be low as compared to the surface of the earth.

It is assumed that the atmospheric pressure is caused due to hydrostatic measurements where the changes caused by weight of air are measured.

Also, it is observed that when there is an  elevation, the atmospheric pressure decreases.

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Wood is made mostly of cellulose and has a chemical formula of C6H1005. Which of
astra-53 [7]

Answer:

Answer below

Explanation:

First to show combustion, you use O₂.

So   C₆H₁₀O₅ +  O₂ is the reaction.  Assuming complete combustion, all you get as products are CO₂ and H₂O.  Then you have to balance the full reaction.

C₆H₁₀O₅  +  6O₂  ----->  6CO₂  +  5H₂O

6 Carbons on each side

10 Hydrogens on each side

17 Oxygens on each side

8 0
3 years ago
YOU DO:
mihalych1998 [28]

Answer:

67.1%

Explanation:

Based on the chemical equation, if we determine the moles of sodium carbonate, we can find the moles of NaHCO₃ that reacted and its mass, thus:

<em>Moles Na₂CO₃ - 105.99g/mol-:</em>

6.35g * (1mol / 105.99g) = 0.0599 moles of Na₂CO₃ are produced.

As 1 mole of sodium carbonate is produced when 2 moles of NaHCO₃ reacted, moles of NaHCO₃ that reacted are:

0.0599 moles of Na₂CO₃ * (2 moles NaHCO₃ / 1 mole Na₂CO₃) = 0.1198 moles of NaHCO₃

And the mass of NaHCO₃ in the sample (Molar mass: 84g/mol):

0.1198 moles of NaHCO₃ * (84g / mol) = 10.06g of NaHCO₃ were in the original sample.

And percent of NaHCO₃ in the sample is:

10.06g NaHCO₃ / 15g Sample * 100 =

<h3>67.1%</h3>
7 0
3 years ago
Name the components of stainless steel​
tatuchka [14]

Explanation:

Composition of Stainless Steel

Steel is an alloy of iron and carbon. Stainless steels are steels containing at least 10.5% chromium, less than 1.2% carbon and other alloying elements

6 0
3 years ago
Find the formula for the hydrate<br>0.737 g MgSO3 and 0.763 g H2O
babunello [35]

The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

To know more about hydrate compound, visit the below link:

brainly.com/question/22411417

#SPJ1

6 0
2 years ago
A student is instructed to make 1 L of a 2.0 M solution of CaCl2 using dry salt. How should he do this?
Pachacha [2.7K]
<span>The student should follow following steps to make 1 L of </span>2.0 M CaCl₂.<span>
<span>
1. First he should calculate the number of moles of 2.0 M CaCl</span></span>₂ in 1 L solution.<span>

</span>Molarity of the solution = 2.0 M<span>
Volume of solution which should be prepared = 1 L

Molarity = number of moles / volume of the solution

Hence, number of moles in 1 L = 2 mol

2. Find out the mass of dry CaCl</span>₂ in 2 moles.<span>

moles = mass / molar mass

Moles of CaCl₂ = 2 mol</span><span>
Molar mass of CaCl₂ = </span><span>110.98 g/mol

Hence, mass of CaCl</span>₂ = 2 mol x <span>110.98 g/mol
                                     = 221.96 g

3. Weigh the mass accurately 

4. Then take a cleaned and dry1 L volumetric flask and place a funnel top of it. Then carefully add the salt into the volumetric flask and finally wash the funnel and watch glass with de-ionized water. That water also should be added into the volumetric flask.

5. Then add some de-ionized water into the volumetric flask and swirl well until all salt are dissolved.

<span>6. Then top up to mark of the volumetric flask carefully. 
</span>
</span>
7. As the final step prepared solution should be labelled.
4 0
2 years ago
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