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3 years ago

Which statement about atmospheric pressure near Earth’s surface is true?

2 answers:

6 0

I think the correct answer from the choices listed above is option B. The statement that is true about the atmospheric pressure near Earth’s surface would be that it decreases as you move away from Earth’s surface. Pressure decreases with increasing altitude. Hope this answers the question.

Dominik [7]3 years ago

6 0

Answer : Option B) It decreases as someone moves away from earth's surface.

Explanation : The atmospheric pressure at the surface of the earth is at maximum, it is seen that as we move away from the surface of the earth the pressure decreases. As on the top of mountains the atmospheric pressure is found to be low as compared to the surface of the earth.

It is assumed that the atmospheric pressure is caused due to hydrostatic measurements where the changes caused by weight of air are measured.

Also, it is observed that when there is an elevation, the atmospheric pressure decreases.

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Which reactant will be used up first if 78.1g of o2 is reacted with 62.4g of c4h10?

dlinn [17]

Answer:

Reagent O₂ will be consumed first.

Explanation:

The balanced reaction between O₂ and C₄H₁₀ is:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

C₄H₁₀: 2 moles
O₂: 13 moles
CO₂: 8 moles
H₂O: 10 moles

Being:

C: 12 g/mole
H: 1 g/mole
O: 16 g/mole

The molar mass of the compounds that participate in the reaction is:

C₄H₁₀: 4*12 g/mole + 10*1 g/mole= 58 g/mole
O₂: 2*16 g/mole= 32 g/mole
CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

C₄H₁₀: 2 moles* 58 g/mole= 116 g
O₂: 13 moles* 32 g/mole= 416 g
CO₂: 8 moles* 44 g/mole= 352 g
H₂O: 10 moles* 18 g/mole= 180 g

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

$mass of O_{2} =\frac{416grams of O_{2}*62.4 grams ofC_{4}H_{10} }{116 grams of C_{4}H_{10}}$

mass of O₂= 223.78 grams

But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, reagent O₂ will be consumed first.

3 0

3 years ago

The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re

Kitty [74]

Answer: The temperature of the system will be 1622 K

Explanation:

The equation relating the pre-exponential factor and activation energy follows:

$\log D=\log D_o-\frac{E_a}{2.303RT}$

where,

D = diffusion coefficient = $2.7\times 10^{-14}m^2/s$

$D_o$ = pre-exponential constant = $1.7\times 10^{-5}m^2/s$

$E_a$ = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

$\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K$

Hence, the temperature of the system will be 1622 K

8 0

3 years ago

Why is it necessary to find the percent yield of a reaction? A. to determine the efficiency of the reaction B. to determine the

Sveta_85 [38]

Answer:

Explanation:

Answer:

A. to determine the efficiency of the reaction

Explanation:

Percentage is the ratio of the actual yield to theoretical yield as a percentage. It is calculated by dividing the actual yield by theoretical yield then multiplying by 100%.

Calculation of percentage yield is important as it helps in the determination of efficiency of a reaction. For example in most industries for the purpose of making the most product with the least waste.

Additionally, calculating the percentage yield helps in determining other products that may be formed during the reactions.

7 0

3 years ago

H fygykg,hyf ggyhgfsdyhcjsgvfufdgyvyghxhjlkfdhgjkygucdsgyifdc \

kirza4 [7]

Well thats a pretty difficult question, I think the answer might be 4

7 0

3 years ago

Read 2 more answers

In a chemical reaction you collect 1000 mL of hydrogen gas at STP how many moles of hydrogen gas did you collect

Katyanochek1 [597]

Since there are 22.4 L/mol at STP, you would convert 1000mL to 1 L then divide that by 22.4, meaning your answer would be 0.0446 rounded to 0.04