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aleksklad [387]
3 years ago
5

Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decaoxide and water. P

H3(g) + O2(g) → P4O10(s) + H2O(g) [unbalanced]Calculate the mass of P 4O 10( s) formed when 225 g of PH 3 reacts with excess oxygen
Chemistry
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

The mass of P₄O₁₀ (s) formed is 471.03 g

Explanation:

4PH₃(g) + 8O₂(g) →  P₄O₁₀ (s)  + 6H₂O (g)

This is the ballanced equation.

Every 4 moles of phosphine, 1 mol of tetraphosphorus decaoxide is generated.

Moles of PH₃ = Mass PH₃ / Molar mass PH₃

Moles PH₃ = 225 g / 33.9 g/m

Moles PH₃ = 6.63 moles

So the rule of three, will be:

If 4 moles of PH₃ generate 1 mol  P₄O₁₀

Then, 6.63 moles of  PH₃ generate (6.63  .1)/4 = 1.66 moles

If we want to know the mass:

Moles . Molar mass = mass

Molar mass  P₄O₁₀  = 283.88 g/m

1.66m  . 283.88 g/m = 471.03 g

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