Answer: pOH = 3.13
Ba(OH)2 is a very basic substance. The general formula for pOH is - log(OH)
Barium Hydroxide produces 2 moles of OH for every mole of Ba(OH)2 present in the solution.
0.00037 M = 3.7 * 10^-4 Ba(OH)2 will produce 2 *0.00037 M of OH-
OH- = 2* 0.00037 = 0.00074
pOH = - log(0.00074) = 3.13
Answer: I think the formula is PV=nRT and I divide both sides by RT, but this is as far as I can get in my equation before I get stumped: (751 mm Hg) (8.3 L)/ (309 K) Can you help?
Explanation:
Answer: The formula of the acid that was neutralized is 
Explanation:
Neutralization is a chemical reaction in which acid and base combine to form salt and water. Acids donate
and bases donate
in water which combine to form water molecules.
As the salt formed is
, the acid must contain
and thus the acid is 
The balanced chemical reaction is ;

The formula of the acid that was neutralized is 
Answer:
<h2>117.94 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have

We have the final answer as
<h3>117.94 moles</h3>
Hope this helps you