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Lena [83]
3 years ago
6

What is 10/16 times 1/15

Mathematics
2 answers:
Darya [45]3 years ago
7 0

The answer is 1/24




good luck hope this helps




Byeeeeeeeee

erica [24]3 years ago
6 0
1/24
Hope this helps!
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Madison is baking party favors she wants to make enough favor so each guest gets the same number of favors she knows there will
iris [78.8K]

Answer:

It would be 24

Step-by-step explanation:

6: 6, 12, 18, 24

8: 8, 16, 24

The least common number is 24, so she should make at least 24.

4 0
4 years ago
Find m/AEB<br><br> A.<br> 10<br> B.<br> 70<br> C.<br> 110<br> D.<br> 170
Paul [167]
A is most likely the answer.

Hope this Helped!

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5 0
4 years ago
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What is the value of minus 6 x cubed minus y squared minus 3 x y if if x = -2 and y = 4
Oksi-84 [34.3K]

Well, "minus 6 x cubed minus y squared minus 3 x y" translates to:

-6x^{2} -y^{2} -3xy

Then, if we insert the values for x and y, we get:

-6(-2)^{2} -(4)^{2} -3(-2)(4)

When we distribute and multiply:

144-16-24

And once we combine like terms:

104<em> is the answer</em>


8 0
4 years ago
Read 2 more answers
3HELP__________________
Brut [27]

Answer:

m∠KIJ = m∠LIM ⇒ answer B

Step-by-step explanation:

* Lets explain how to solve the problem

∵ I is the mid-point of NH

∴ IN = IH

- MJ is perpendicular to NH and passes through I the mid-point of NH

∴ MJ is perpendicular bisector of NH

- NH ⊥ MJ and intersects it at I

∴ m∠NIM = m∠NIJ = 90°

- ∠ NIM consists of two angles ∠NIL and ∠MIL

∵ m∠NIM = m∠NIL + m∠MIL

- ∠NIJ consists of two angles ∠NIK and ∠JIK

∵ m∠NIJ = m∠NIK + m∠JIK

∴ m∠NIL + m∠MIL = m∠NIK + m∠JIK ⇒ (1)

∵ NH bisects ∠KIL

∴ m∠NIL = m∠NIK ⇒ (2)

- From (1) and (2)

∴ m∠MIL = m∠JIK

* m∠KIJ = m∠LIM

7 0
3 years ago
Please help and find the missing side x
faltersainse [42]

\text{Hello there!}\\\\\text{A simple way to find the value of x is to find the scale factor}\\\\\text{When you flip the shapes to make it look exactly the same,}\\\text{you would see that the numbers are divisible to it}\\\\\text{Side 21 is congruent to side 3}\\\\\text{Divide 21 by 3 and you'll get 7 (1/7 sine we're going to a smaller shape)}\\\\\text{The x side is congruent to the 91 side}\\\\\text{Divide 91 by 7}\\\\91\div7=13\\\\\large\boxed{x=13}

7 0
3 years ago
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