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3 years ago

Divide -5/12 and -5/8

Mathematics

2 answers:

kiruha [24]3 years ago

5 0

Answer:

2/3

Step-by-step explanation:

-5/12 ÷ -5/8

Copy dot flip

-5/12 * -8/5

The 5's cancel

-8/-12

Divide the top and bottom by -4

2/3

sesenic [268]3 years ago

4 0

Answer:

2/3

Step-by-step explanation:

-5/12 divided by -5/8

To solve this you need to change the division sign to a multiplication sign.Then find the reciprocal of the second fraction. It should look like this.

-5/12*-8/5

Then you multiply straight across

5*8=40

5*12=60

40/60

This can be simplified to 2/3

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Find the volume of this cylinder give your answer to 1dp 20cm 9cm

vlada-n [284]

Answer:

this is a required answer.

5 0

2 years ago

What is the value of 9x^2 + 13x – 15, if x = 2

Paladinen [302]

Step-by-step explanation:

Given,

$9 {x}^{2} + 13x - 15$

and

$x = 2$

Substitute x = 2 into expression.

$9 {x}^{2} + 13x - 15 = 9( {2}^{2} ) + 13(2) - 15 \\ = 9(4) + 26 - 15 \\ = 36 + 26 - 15 \\ = 62 - 15 \\ = 47$

3 0

3 years ago

Read 2 more answers

Write the computer program for;urgent

AlladinOne [14]

ANSWER:

#include <stdio.h>

#define PAYRATE 10 //basic pay rate per hour

#define OVERTIME 15 //in excess of 40 hours a week

int NetPay(int hours);

int main()

{

int userWeeklyHours;

printf("Please enter your total weekly working hours: \n");

scanf("%d", &userWeeklyHours);// get the user weekly hours

NetPay(userWeeklyHours);

return 0;

}

int NetPay(int hours)// implementing the function to calculate total pay, total taxes, and net pay

{

int firstRate, secondRate, restOfRate, secondAmount, rest, payAfterTax, payedBeforeTax, overHours;

if (hours > 40)

{

overHours = hours - 40;

payedBeforeTax = (40 * PAYRATE) + (overHours * OVERTIME);

}

else

payedBeforeTax = hours * PAYRATE;//defining the user first paycheck before taxes

if (payedBeforeTax <= 300)//paying only first rate case

{

firstRate = payedBeforeTax*0.15;

payAfterTax =payedBeforeTax - firstRate;

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate, payAfterTax);

}

else if (payedBeforeTax > 300 && payedBeforeTax <= 450)//paying first and second rate

{

secondAmount = payedBeforeTax - 300;

firstRate = (payedBeforeTax - secondAmount) * 0.15;

secondRate = secondAmount * 0.20;

payAfterTax = payedBeforeTax - (firstRate + secondRate);

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate + secondRate, payAfterTax);

}

else if (payedBeforeTax > 450)// paying all rates

{

rest = payedBeforeTax - 450;

secondAmount = (payedBeforeTax - 300) - rest;

firstRate = (payedBeforeTax - (rest + secondAmount)) * 0.15;

secondRate = secondAmount * 0.20;

restOfRate = rest * 0.25;

payAfterTax = payedBeforeTax - (firstRate + secondRate + restOfRate);

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate + secondRate + restOfRate, payAfterTax);

}

return payAfterTax;

}

8 0

3 years ago

. Find the value of x. If necessary, round to the nearest tenth. 6.9 in. 9.7 in. 11.7 in. 13.7 in.

solong [7]

I think the answer is -12

7 0

3 years ago

When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f

Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

$P(A) = 0.0286 + 0.1*0.9714 = 0.12574$

Probability of you winning and fireworks going off:

100% of 1/35, so $P(A \cap B) = 0.0286$

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275$

0.2275 = 22.75% probability that you actually won that round

8 0

3 years ago