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Shkiper50 [21]
4 years ago
15

Using relative enthalpy and entropy values, determine how the process is affected after each of the following temperature or pre

ssure changes. Consider that a more effective reaction produces more product or more product in a shorter amount of time.
Reaction: SO₂ (g) + 2H₂S (g) ↔ 3S(s) + 2H₂O (g)Substance | ΔG kJ/mol | ΔH kJ/molH₂O(g) | -228.6 | -241.8H₂O(l) | -237.1 | -285.8SO₂(g) | -300.4 | -296.9SO₃(g) | -370.4 | -395.2H₂S(g) | -33.01 | -20.17S(s) | 0 | 0Categorize into: "More Effective" ~ "Less Effective" ~ "Equally Effective"a. Temp. decreases while maintaining container sizeb. Temp. increases while maintaining container sizec. Pressure decreases while maintaining container sized. Pressure increases while maintaining container size
Chemistry
1 answer:
amm18124 years ago
8 0

Answer:

a. More effective.

b. Less efective.

c. More effective.

d. Less effective.

Explanation:

For the reaction:

SO₂ (g) + 2H₂S (g) ⇄ 3S(s) + 2H₂O (g)

It is possible to obtain ΔG and ΔH of the reaction from the standard ΔG and ΔH of products minus standard ΔG and ΔH of reactants. Thus, ΔG of reaction is:

ΔGr = 3ΔG S(s) + 2ΔG H₂O (g) - ( ΔG SO₂ (g) + 2ΔG H₂S (g))

ΔGr = 3×0 kJ/mol + 2×-228,6 kJ/mol - (-300,4 kJ/mol + 2×-33,01 kJ/mol)

ΔGr = <em>-90,78 kJ/mol</em>

In the same way, ΔHr is:

ΔHr = ΔH S(s) + 2ΔH H₂O (g) - ( ΔH SO₂ (g) + 2ΔH H₂S (g))

ΔHr = 3×0 kJ/mol + 2×-241,8 kJ/mol - (-296,9 kJ/mol + 2×-20,17 kJ/mol)

<em>ΔHr = -146,36 kJ/mol</em>

A ΔH < 0 means that the reaction is producing heat. By Le Chatelier's principle (Changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system), <em>the increasing of temperature will produce less product</em>, in the same way, <em>the decreasing of temperature will produce more product.</em>

Thus,

a. More effective.

b. Less efective.

As 2 moles of gas produce 5 moles of gas <em>if the pressure decreases the system will try to produce more gas</em> opposing the change, and again <em>if the pressure increases the system will try to produce less gas.</em>

Thus:

c. More effective.

d. Less effective.

I hope it helps!

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Predict the splitting pattern for each of the labeled hydrogens in the following molecules. Assume that all coupling constants a
Ghella [55]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) Splitting pattern for Ha= 2+1 , Triplet

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Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

b) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

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For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

c) The IUPAC name is Butan-2-ol

Explanation:

Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.

According to that for molecule 1 as shown on the second uploaded image

For Proton Ha, number of non equivalent protons n= 2

Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

Considering the second question for Molecule 2 as shown on the third uploaded image  

For Proton Ha, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

For Proton Hb, number of non equivalent protons n= 3

Splitting pattern for Hb= 3+1=4 , Quartet

For Proton Hc, number of non equivalent protons n= 3

Splitting pattern for Hc= 3+1=4 , Quartet

For Proton Hd, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

Considering the third question

The name of the given molecule  is gotten according to longest carbon chain  = 4 (Prefix 'Butan')

Functional group = -OH (Suffix 'ol') at C-2

The IUPAC name is Butan-2-ol

3 0
3 years ago
What is the pressure in a container that has 3 atm H2, 2 atm of N2 and 5 atm of F2?
LekaFEV [45]
<h3>Pressure has additive properties meaning that if you add the partial pressures together, you obtain total pressure.  P total = P1 + P2 + P3 + ...  Pressure of container = pressure of H2 + Pressure of N2 + Pressure of F2                                          = 3atm + 2atm + 5atm                                                        = 10atm    Hope that helped. ;)</h3>
7 0
3 years ago
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔGo:reactio
koban [17]

Answer:

Explanation:

glucose-1-phosphate  →  glucose-6-phosphate,  ΔGo = -7.28 kJ/mol

fructose-6-phosphate → glucose-6-phosphate,    ΔGo = -1.67 kJ/mol

subtracting the equation

glucose-1-phosphate - fructose-6-phosphate  = 0 , ΔGo =  -7.28  - ( -1.67 ) kJ / mol

glucose-1-phosphate  = fructose-6-phosphate      ΔGo  = - 5.61 kJ / mol

- ΔGo = RT lnK

5.61 x 10³ = 8.31 x 298 x lnK

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3 years ago
Hund's rule states that electrons must spread out within a given subshell before they can pair
Temka [501]

Answer:

Groups 14, 15, and 16 have 2,3, and 4 electrons in the p sublevel (p sublevel has 3 "spaces" AKA orbitals), because Hunds says one in each orbital before doubling up if you had 2 electrons, group 14, they would both be in the first orbital, with 3 electrons, group 15, two in the first orbital one in the 2nd none in the 3rd. With 4 electrons, group 16, then you would have 2 in the first 2 orbitals and NONE in the 3rd.

Explanation:

If you are in group 13 you only have 1 electron so it can only be in one orbital. with group 17, you have 5 electrons, so 2 in the first 2 in the second and 1 in the 3rd, correct for Hunds rule anyway. Noble gasses, group 18, have 6 elecctrons, so every orbital is full any way you look at it.

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3 years ago
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katovenus [111]

The balanced chemical reaction is:

<span>Mg(OH)2  +  2HCl  -->  MgCl2  +  2H2O</span>

 

So we can see that 2 moles of HCl reacts for every 1 mole of Mg(OH)2.

moles HCl left = 0.125 M * 0.150 L – (0.125 M * 0.040 L) * 2

moles HCl left = 0.00875 mol

 

So the concentration of H+ ion is:

[H+] = 0.00875 mol / (0.150 L + 0.040 L)

[H+] = 0.046 M

 

So the pH is:

pH = - log 0.046

<span>pH = 1.34</span>

5 0
4 years ago
Read 2 more answers
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