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Elodia [21]
3 years ago
7

1) Calculate the average speed in meters/minute for the trip represented

Chemistry
1 answer:
Pie3 years ago
8 0

Answer:

in physics we never work with minutes only seconds.

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A solution is prepared by dissolving 318.6 g sucrose (C12H22O11) in 4905 g of water. Determine the molarity of the solution
alexandr1967 [171]

The molarity of sucrose solution is 0.19 M.

The molarity of HCl is 12.8 M.

<u>Explanation:</u>

a. Molarity can be found by finding its moles and volume of water in L and then dividing both(moles divided by volume in Litres).

Mass of sucrose = 318. 6 g

Molar mass of sucrose = 342.3 g/mol

Moles = $\frac{mass}{molar mass}

       = $\frac{318.6 g}{342.3 g/mol}

      = 0.93 moles

Mass of water = 4905 g

Density of water = 1000 g/L

Volume = $\frac{mass}{density}

             = $\frac{4905 g }{1000 g/L}

          = 4.905 L

Now we can find the molarity = $\frac{moles}{Volume(L)}

                               =  $\frac{0.93 moles}{4.905 L}

                              = 0.19 M

So the molarity of sucrose solution is 0.19 M.

b. The molarity of HCl can be found as follows.

It is given that 39% HCl that means it contains 39 g of acid in 100 g of water.

Density of the solution is 1.20 g/mL, from this mass can be found as,

$\frac{1 L \times 1000 mL \times 1.20 g}{1 L \times 1 mL}

= 1200 g

Now we have to find out the amount of HCl in grams as,

$\frac{1200g \times 39 g HCl }{100 g solution}

= 468 g HCl

Now we have to find the number of moles,

moles = $\frac{468 g}{36.46 g/mol}

           = 12.8 moles

Molarity of HCl = $\frac{12.8 moles}{1 L }

                          = 12.8 M

So the molarity of HCl is 12.8 M.

6 0
3 years ago
The element gallium has two stable isotopes. About 60% of the gallium atoms found are gallium-69, while the remaining 40% are ga
Varvara68 [4.7K]

Answer:

70 amu

Explanation:

The average atomic mass of an element is calculated by first finding the products of the atomic masses of the isotopes of that element and their respective percent abundances. The second/last step is finding the sum of those products, applying significant figures rules throughout. In this case, you would do the following:

(69 x 60%) + (71 x 40%) =  70 amu (with significant figures rules applied)

Cheers

4 0
3 years ago
When we looked at assigning the electrons in nitrogen to sites in the 2s and 2p orbitals, we used the 2s anti-bonding site. Whic
AveGali [126]

Answer:

B) Although this site is not desirable for making a bond between atoms, it is a good site in the sense that the electrons can be close to the nucleus.  

Explanation:

An antibonding orbital points away from the nuclei, with a node between them, so the electrons are not held close to the nuclei. The orbital is not desirable for bonding.

The diagram below shows a σ*1s molecular orbital, but a σ*2s orbital has a similar shape.

A) is true. The σ*1s orbital has the lowest energy.

C) is true. Any orbital can accommodate at most one electron pair.

D) is may be true. Orbital energy decreases as atomic number increases, so the orbital energy of an N₂ σ*2s molecule may be close to that of a sulfur atom's 2s orbital.

6 0
4 years ago
2) write down two examples of mixtures<br>and state their use in daily life.<br><br>​
prisoha [69]

Answer:

<em>first </em><em>example</em><em> </em><em>is</em><em>. </em><em>Air </em><em> </em><em>it </em><em>is </em><em>mixture </em><em>of </em><em>many </em>

<em>gases </em><em> </em>

<em>it's </em><em>us </em><em> </em><em>it </em><em>keeps </em><em>us </em><em>alive </em><em> </em><em>and </em><em>many </em><em>more </em><em>uses</em>

<em>second </em><em>example</em><em> </em><em>is </em><em>water </em><em>is </em><em>also </em><em>a </em><em>mixture</em><em> </em>

<em>made </em><em>up </em><em>of </em><em>carbon </em><em>and </em><em>hydrogen</em><em> </em>

<em>and </em><em>its uses </em><em>is </em><em>to </em><em>fulfill</em><em> </em><em>our </em><em>needs </em>

<em>hope </em><em>it </em><em>helps</em>

7 0
3 years ago
What is "Scarcity" <br><img src="https://tex.z-dn.net/?f=." id="TexFormula1" title="." alt="." align="absmiddle" class="latex-fo
Lana71 [14]

Explanation:

I don't know sorry ok I have some work so I m sorry

4 0
3 years ago
Read 2 more answers
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