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LekaFEV [45]
3 years ago
15

Select the correct answer. Which type of committees handle recurring tasks in an organization? A. task force B. standing C. ad h

oc D. generic
Physics
2 answers:
VashaNatasha [74]3 years ago
6 0

Answer:

Select the correct answer. Which type of committees handle recurring tasks in an organization?

B. standing

~batmans wife dun dun dun...

viva [34]3 years ago
4 0

Answer:

Standing :)

Explanation:

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You lift a stuffed toy up above the ground (over your head).
BigorU [14]

Answer:

Gravitational energy

Explanation:

when over head , when it hits the floor thermal energy

7 0
2 years ago
Willingness to take turns is one way we can express our attitudes in
Ilia_Sergeevich [38]
<span>The correct option is A, that is, non-verbal communication. Non-verbal communication is defined as the kind of communication that are passed across without using words. Examples of this are: shaking of hands, hugging, back-patting, facial expression, eye-contact and every form of communication that are make use of without the usage of words.</span>
7 0
3 years ago
1. A kangaroo hops 84 m to the east in 7 seconds.
DENIUS [597]

Explanation:

Given parameters:

Distance hopped  = 84m

Displacement  = 84m due east

Time  = 7s

Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

    Speed  = \frac{distance}{time }   = \frac{84}{7}  = 12m/s

  Velocity  = \frac{displacement}{time}   = \frac{84}{7}   = 12m/s due east

3 0
3 years ago
A bird flies overhead from where you stand at an altitude of 270.0ĵ m and at a velocity horizontal to the ground of 14.0î m/is.
Varvara68 [4.7K]

Answer:

L = 8694 Kg.m²/s

Explanation:

r = 270 ĵ m

v = 14 î m/s

m = 2.3 kg

θ = 90º

L = ?

We can apply the equation

L = m*v*r*Sin θ

L = (2.3 kg)*(14 m/s)*(270 m)*Sin 90º = 8694 Kg.m²/s

8 0
3 years ago
A series of pulses, each of amplitude 0.1 m, is sent down a string that is attached to a post at one end. The pulses are reflect
AleksAgata [21]

Answer:

 A_resulting = 0.2 m

Explanation:

Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.

With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is

           A_res = 2A

           A_resultant = 2 .01

           A_resulting = 0.2 m

8 0
2 years ago
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