Question

a girl throws a marshmallow that lands in her friends mouth 92m away. The girl threw the marshmallow at an angle of 67 degrees. How hard was did she throw the marshmallow?

Answer 1

The answer is 25 miles per hour

Answer 2

Answer:

The girl threw the marshmallow with a speed  of 35.4 m/s.

Explanation:

Use the formula for the range of projectile motion:

$R = \frac{v^2\cdot \sin2\theta}{g}$

with R the range or distance (92m), theta the elevation angle (67 degrees) and g the gravitational acceleration. The velocity can be determined from this as follows:

$|v| = \sqrt{\frac{R\cdot g}{\sin 2 \theta}} = \sqrt{\frac{92m\cdot 9.8 \frac{m}{s^2}}{\sin 134^\circ}}=35.40\frac{m}{s}$

The girl threw the marshmallow with a speed  of 35.4 m/s, which is approximately 79 mph. No word on the boy's condition after the marshmallow's landing.