Hi!
The linear velocity is given by:
v = ωR
And ω is given by: ω = 2π/T (where T is the time for 1 revolution)
Now, put these equations together:
v = 2πR/T
If it takes 5 seconds for 10 revolutions, then it takes 5/10 = 0.5 seconds for each revolution.
V = (2π * 2)/0.5
V = 4π/0.5
V = 8π rad/s
Then, we goes to the centripetal acceleration:
a = V²/R
a = 64π²/2
a = 32π² rad/s²
;)
Answer:2.103 m/s
Explanation:
Given
mass of sports car
mass of SUV
Suppose u is the velocity if sports car before collision
Conserving momentum we get
After collision the combined mass drag 2.8 m and finally stops
From work energy theorem work done by friction is equal to change in kinetic energy of the combined mass system
where
Initial velocity
Answer:
c = 3.00E108 m/s = 3.00E5 km/s
t = S / v = 3.84E5 / 3.00E5 = 1.28 sec
Answer:
Explanation:
If a number of less than 1, then the number has a decimal point like
0.085, 0.008 e.t.c.
The zeros before the none zero digit are insignificant. The significant figure is 8 and 5.
But if there a zero between the none zero e.g. 0.0087056
Here the zero between 7 and 5 is significant, then the significant numbers are 8,7,0,5,6
But if the zero is not in between the none zero digit, then the zero is insignificant
E.g 0.05800
The last two zero is insignificant, the significant number is 5 and 8
So, If a positive numbers less than 1, the zeros between the decimal point and a non-zero number are NOT significant.