Answer:
a) T=549.36N Upwards
b) T=448.56N Upwards
c) T=650.16N Upwards
Explanation:
The very first thing we can do to solve this problem is to draw a free body diagram we can use to analyze the situation (see attached picture).
On the diagram we can see there are only two forces acting on the object: the tension of the rope and the weight of the object itself.
a)
Since the object is moving at a constant speed, this means that its acceleration will be zero. So we can do a sum of forces like this:
T-W=0
T=W
T=mg
T=549.36N upwards
b)
For part b, since the object is accelerating downwards, we wil say that it's acceleration is negative, so
so we can do a sum of forces again:
so
T-W=ma
T=ma +W
T=ma+mg
T=m(a+g)
and now we substitute:
which yields:
T=448.56N upwards (in this particular case, the tension always goes upwards)
c)
Since the object is moving upwards, we can say that its acceleration will be positive, so
we can take the solved equation we got on the previous part of the problem, so we get:
T=m(a+g)
which yields:
T=650.16N upwards
Answer:Principle of rectilinear propagation of light
Explanation:Principle of rectilinear propagation of light
Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. ... It is because light travels along a straight line and leaves only the areas where the object interferes.
Answer:
Here, 5% of energy wasted as a heat lost or work done against frictional forces.
Explanation:
No engine has yet made that can convert its all input energy into mechanical energy. Some of the input energy goes in vain in the form of heat and friction.
Answer:
(a) Ratio of mean density is 0.735
(b) Value of g on mars 0.920
(c) Escape velocity on earth is
Explanation:
We have given radius of mars and radius of earth
Mass of earth
So mass of mars
Volume of mars
So density of mars
Volume of earth
So density of earth
(A) So the ratio of mean density
(B) Value of g on mars
g is given by
(c) Escape velocity is given by