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3 years ago

All objects have an electric charge, what are the options they could have select all that apply.

Physics

1 answer:

borishaifa [10]3 years ago

3 0

All of the answers apply because any object can have positive, negative or neutral charges depending on their atoms

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Hlp

Nadusha1986 [10]

Answer:

i think its C. cools

Explanation:

7 0

3 years ago

Read 2 more answers

When an experiment is replicated, how should the results of the two experiments compare?

Lelu [443]

The results of the experiments should be similar.

7 0

3 years ago

Read 2 more answers

Ted lifts a 10N weight at a height of 1.5 m in 1 second. Johnny lifts a 10N weight at a height of 1.5 m in 2 second. Which state

fenix001 [56]

Answer:

he affirmations the correct ones are: A and D

Explanation:

To find out which expressions are correct, let's calculate the work and power done by each person

the expression for work is W = F and

the expression for power is P = W / t

In this case the work is positive because the beast is in the same direction of displacement.

Ted

W₁ = 10 1.5

W₁ = 15 J

P₁ = 15/1

P₁ = 15 w

Johnny

the job

W₂ = 10 1.5

W₂ = 15 J

the potential

P₂ = 15/2

P₂ = 7.5 w

therefore we see that the work of both is the same, but Ted developed twice as much power as Johnny

when resisting the affirmations the correct ones are: A and D

3 0

3 years ago

A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th

Elis [28]

Answer:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

$y=y_0+V_0t-gt^2/2$

We are only interested in the vertical motion, so that equation is all what you need.

1. Water ballon is thrown horizontally at sped 2.00 m/s.

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

$y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s$

2. Water ballon thrown straight down at 2.00 m/s

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

$0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s$

To solve the equation you can use the quadratic formula.

$t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92$

You get two times. One of the times is negative, thus it does not have physical meaning.

3. Conclusion:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0

3 years ago

In a summer storm, the wind is blowing at a velocity of 8 m/s north. Suddenly in 3 seconds, the winds velocity is 23 m/s north.

cricket20 [7]

Answer:a=v-u/t

=23-8/3

=5m/s hope you got your answer

Explanation:

8 0

3 years ago