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3 years ago

A hurricane is a type of serve cyclone which statement best explains how a hurricane forms

Chemistry

1 answer:

storchak [24]3 years ago

7 0

Answer:

Hurricanes form over the warm ocean water of the tropics

Explanation:

when war, moist air over the water rises , it is replaced by cooler air

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Can someone please please help me with this? I will mark you as brainlist? I only have two more questions but anyways

DENIUS [597]

Answer:

its 20 L

Explanation:

7 0

3 years ago

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The element silver exists in nature as two isotopes: 107Ag has a mass of 106.9051 u, and 109Ag has a mass of 108.9048 u. The ave

Lilit [14]

Answer:

107Ag has abundance of 51.7%

109Ag has abundance of 48.3%

Explanation: Please see attachment for explanation

3 0

3 years ago

Iron-59 has a half-life of 45.1 days. how old is an iron nail if the fe-59 content is 25% that of a new sample of iron? show all

Yuliya22 [10]

I have attached a paper with the answer. hope you understand. let me know if you have any question

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3 years ago

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On 100 corex

Julli [10]

Answer:

P(total) = 164 mmHg

Explanation:

Given data:

Partial pressure of helium = 77 mmHg

Partial pressure of nitrogen = 87 mmHg

Total pressure of flask = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this problem by using this law.

P(total) = P(He) + P(N₂)

P(total) = 77 mmHg + 87 mmHg

P(total) = 164 mmHg

3 0

3 years ago

What is the molarity of 555 L of a Ba(OH)2 solution if the pH is 10.20?

Kipish [7]

pH is a symbolic representation of:

$pH=-\log \lbrack H^+\rbrack$

and for water we now that:

$\lbrack H^+\rbrack\lbrack OH^-\rbrack=10^{-14}$

that means the text give us the information to calculate the concentration of protons and therefore the concentration of ions OH-:

$pH=10.2\rightarrow\lbrack H^+\rbrack=10^{-10.2}^{}$

therefore the concentration of OH- can be calculated:

$\lbrack OH^-\rbrack=\frac{10^{-14}}{10^{-10.2}}=10^{-3.8}=1.58\times10^{-4}\text{ M}$

but they are not asking about the concetration of OH- they ask about concentration of Ba(OH)2 and for that we need to know the disolution stechiometry

$Ba(OH)_2\rightarrow Ba^++2\times OH^-$

Whic mean the concentration of Ba(OH)2 is half the concentration of OH-:

$\lbrack Ba(OH)_2\rbrack=\frac{\lbrack OH^-\rbrack}{2}=7.92\times10^{-5}M$

4 0

1 year ago