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Sliva [168]
3 years ago
5

When the temperature of the gas changes from cold to hot, the amount of pressure is ___________.

Chemistry
1 answer:
Klio2033 [76]3 years ago
6 0
The pressure would increase. When the temperature change form cold to hot, the gas will find ways to escape from containment. Thus, if it cannot escape that pressure will keep on increasing as the temperature rises.
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45. Which electron configuration represents an
uysha [10]

Answer:

The correct answer is - (4) 1s2 2s2 2p5 3s2

Explanation:

An excited state is a state when the valence electron has moved to some other higher energy orbital, from its ground state orbital. The ground state has a lower energy level or sublevel. In this case, the higher energy level orbit fills before the lower energy level.

In option 4, the last electron is filled in higher energy orbit 3s2 before filling the lower or ground energy level 2p5, in the ground state it would be 1s2 2s2 2p6 3s1 instead of 1s2 2s2 2p5 3s2.

Thus, the correct answer is option 4.

3 0
3 years ago
When 12 moles of o2 react with 1.1 mole of c10h8 what is the limiting reactant?
Trava [24]
1.1   moles   of C10H8  is the  limiting  reagent  in   the  reaction between   reaction  C10H8   and   O2
.
C10H8  +  12O2  ---->  10CO2   + 4H2O

C10H8  is  the  limiting   reagent   since   1.1  moles  of  C10H8  is  totally   consumed   during  the  reaction
6 0
3 years ago
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As the amount of charge on two objects increases, the strength of the electrical force between the objects
Aleks [24]

Answer:

Increase is the answer

Explanation:

Increase is the answer hopes this helps you

6 0
3 years ago
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How many protons does carbons have?
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Carbon has 6 protons
4 0
3 years ago
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At a certain temperature, 0.740 mol of so3 is placed in a 4.00 l container. so_{3}(g)\rightleftharpoons 2so_{2}(g)+o_{2}(g) at e
Phoenix [80]

Answer : The equilibrium constant kc is 4.76 x 10⁻³

Explanation :

The given equilibrium reaction is

2SO_{3} (g) \leftrightarrow 2SO_{2} (g) + O_{2} (g)

Step 1 : Set up ICE table

Let us set up an ICE table for this reaction .

The initial concentration of SO₃ is

Concentration = \frac{mol}{L} = \frac{0.740mol}{4L} = 0.185 M

The initial concentrations of products are 0.

Let us assume x is the change .

Please refer the attached picture.

Step 2 : Use the given value to find x

From the ICE table, we can see that at equilibrium, concentration of O₂ is x

But we have been given that , at equilibrium we have 0.190 mol of O₂ .

Let us convert this to concentration unit.

Concentration of O₂ at equilibrium = \frac{mol}{L} = \frac{0.190mol}{4L} = 0.0475 M

But concentration of O₂ from the ICE table is x.

Therefore we have x = 0.0475 M

Step 3 : Using x , find equilibrium concentrations

Using this value, let us write the equilibrium concentrations of the given species.

[SO₃]eq = 0.185 M - 2x = 0.185 - 2(0.0475) = 0.09 M

[SO₂]eq = 2x = 0.095 M

[O₂]eq = x = 0.0475 M

Step 4 : Set up equation for kc and solve it

The equilibrium constant kc is calculated as,

k_{c} = \frac{[SO_{2}]^{2} [O_{2}]}{[SO_{3}]^{2}}

Let us plug in the above equilibrium values.

k_{c} = \frac{(0.095)^{2} (0.0475)}{(0.09)^{2}}

k_{c} = \frac{0.00042869}{0.09}

k_{c} = 4.76 \times 10^{-3}

The equilibrium constant kc is 4.76 x 10⁻³

3 0
3 years ago
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