The balanced chemical reaction is:
C4H10 + 5O2 = 4CO2 + 2H2O
We are given the amount of butane to be used in the reaction. This will be the starting point of the calculations.
2.50 g C4H10 ( 1 mol C4H10 / 58.14 g C4H10) ( 4 mol CO2 / 1 mol C4H10 ) = 0.21 mol CO2
V = nRT / P = 0.21 mol CO2 (0.08206 atm L/mol K) 320.15 K / 1.04 atm = 5.30 L CO2
Answer : The concentration of and at equilibrium is, 0.0031 M and 0.0741 M respectively.
Explanation : Given,
Moles of = 0.166 mol
Volume of solution = 2.15 L
First we have to calculate the concentration of
Now we have to calculate the concentration of and at equilibrium.
Initial conc. 0.0772 0 0
At eqm. 0.0772-x x x
The expression for equilibrium constant is:
By solving the term, we get the value of 'x'.
x = 0.0741
Thus,
The concentration of at equilibrium = (0.0772-x) = (0.0772-0.0741) = 0.0031 M
The concentration of at equilibrium = x = 0.0741 M
pH(D) A compound that increases the hydroxide ions (OH-) when it is dissolved in a solution
Examples of pure substances include tin, sulfur, diamond, water, pure sugar, table salt and baking soda. Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances which are chemical elements. All elements are pure substances.