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Ksenya-84 [330]
3 years ago
13

The density is 5.4 g/mL and the volume is 12.9 mL.

Chemistry
1 answer:
marishachu [46]3 years ago
5 0

Answer:

69.66 g

Explanation:

We have the following from the question;

Density of the substance = 5.4 g/ml

Volume of substance = 12.9 ml

Mass of substance= the unknown

Since we have both density and volume of the substance, the question must be for us to obtain the mass of the substance, hence;

Density= mass/volume

Mass= Density × volume

Mass = 5.4 g/ml × 12.9 ml

Mass= 69.66 g

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D. She is not right, because there will be more successful collisions

between reactants in the concentrated solutions.

7 0
3 years ago
Read 2 more answers
How much energy is required to vaporize 0.5kg of water?
White raven [17]

Answer:

Explanation:

Vaporization Equation => Q = m·ΔHv

m = 0.5Kg water = 500g water

ΔHv = Heat of vaporization = 540 calories/gram

∴Q = 500g x 540cal/g = 270,000 calories x 4.184 joules/cal = 1,129,680 joules = 1130 Kilojoules (3 sig. figs.)

3 0
3 years ago
Perform the following conversions:
ololo11 [35]

Answer:

a) 20^0C and 293K

b) 437K and 327.2^0F

c) -273^0C and 459.44^0F

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C , ^0Fand K  

These units of temperature are inter convertible.

t^0C=(t+273)K

t^oC=\frac{5}{9}\times (t^oF-32)

K-273=\frac{5}{9}\times (^oF-32)

a)  68°F (a pleasant spring day) to °C and K.

Converting this unit of temperature into ^0C and K by using conversion factor:

t^oC=\frac{5}{9}\times (68^oF-32)

t=20^0C

20^0C=(20+273)K=293K

b) 164°C (the boiling point of methane, the main component of natural gas) to K and °F

Conversion from degree Celsius to Kelvins  and Fahrenheit

164C=\frac{5}{9}\times (t^oF-32)

t^0F=327.2

164°C=(164+273)K=437 K

c) 0K (absolute zero, theoretically the coldest possible temperature) to °C and °F.

K-273=\frac{5}{9}\times (t^oF-32)

0-273=\frac{5}{9}\times (t^oF-32)

t=-459.4^0F

t^K=(0-273)^0C=-273^0C

8 0
3 years ago
In a certain city, electricity costs $ 0.18 per kW ⋅ h . What is the annual cost for electricity to power a lamppost for 5.00 h
LuckyWell [14K]

Answer:

The cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

Explanation:

Cost of electricity = $ 0.18 per KW-H

Time = 5 hour per day

Bulb power = 100 W = 0.1 KW

Fluorescent bulb power = 25 W = 0.025 KW

(a) Cost of electricity for 100 W power bulb

0.1 × 5 × 365 × 0.18 =  $ 32.85

(b) Cost of electricity for 0.025 W  fluorescent  bulb

0.025 × 5 × 365 × 0.18 = $ 8.2125

Therefore the cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

6 0
3 years ago
Predict the precipitate produced by mixing an Al(NO3)3 solution with a NaOH solution. Write the net ionic equation for the react
weqwewe [10]
Al(NO3)3(aq) + 3NaOH(s) --> Al(OH)3 (s) + 3NaNO3 (aq)

The precipitate here is Al(OH)3 (s), since the solid reactant is the precipitate in the aqueous solution. Usually, it is okay to assume in basic chemistry that the transition metal is going to be part of the compound that is the precipitate, especially in an acidic salt and a strong base reaction that we have here.
4 0
3 years ago
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