Question

If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?

Answer 1

Answer:

The answer is 14.29 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\%$

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

$P(\%) = \frac{0.1}{0.7} \times 100 \\ = 14.285714...$

We have the final answer as

14.29 %

Hope this helps you