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zubka84 [21]
3 years ago
13

If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?

Chemistry
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

<h2>The answer is 14.29 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

P(\%) =  \frac{0.1}{0.7}  \times 100 \\  = 14.285714...

We have the final answer as

<h3>14.29 %</h3>

Hope this helps you

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3 years ago
Help me with this question please
mash [69]

<u>Answer:</u>

a. Oxidising agent: Cl₂

b. Reducing agent: NaBr

c. Oxidised: NaBr

d. Reduced: Cl₂

e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1

f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0

<u>Explanation:</u>

Oxidising agents reduces themselves, oxidising other elements/compounds.

Reducing agents oxidise themselves, reducing other elements/compounds.

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Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.

6 0
1 year ago
How does carbon cycle through the ocean, atmosphere, soil, and biosphere?
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make sure to paraphrase and give thanks:) good luck
3 0
3 years ago
Consider a galvanic cell consisting of the following two redox couplesAlB+ 3e Al , Mga + 2e Mg, (ag. E® = 1.676 V ) E° = 2.356 V
malfutka [58]

Answer:

0.68 V

Explanation:

For anode;

3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

2Al^3+(aq) + 6e -----> 2Al(s)

Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

E°anode = -2.356 V

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E°cell= 0.68 V

4 0
2 years ago
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