Answer: Friction
Explanation:
Friction and the normal force would be the two initial forces to overcome.
Answer:
0. 3 s
Explanation:
The motion of the boat is up and down in simple harmonic with amplitude of 20 cm . Time period of oscillation T = 3.5 s and top extreme point is at level with the boarding dock .
The traveller has to wait until the boat reaches middle point ( 1o cm . ) that is half its equilibrium position of oscillation .
Time period is 3.5 s . During its oscillation from extreme top position to its half of the equilibrium position , that is 10 cm below the stationary dock , time taken by boat
t = T / 12 = 3.5 /12 = .3 s .
Man shall have to wait for a period of 0.3 s
Ans 0. 3 s .
Answer:
I believe D
Explanation:
I'm not for sure but I think it is D
Answer:
a) 15.23 roods
b) 15487.15 m²
Explanation:
Given:
Area of plowed land = 2.74 Acres
Livestock area = 24.3 perches by 5.47 perches
Now,
a) Total area = 3 acres + (24.3 perches + 5.47 perches)
also,
1 acre = 40 perches by 4 perches
thus,
Total area = 3 × (40 perches × 4 perches) + (24.3 perches + 5.47 perches)
or
Total area = 480 perch² + 132.921 perch²
Or
Total area = 612.921 perch² .................(1)
Also,
1 rood = 40 perches × 1 perches = 40 perch²
thus,
1 perch² = 1/40 rood
therefore,
612.921 perch² = 612.921 × 1/40 rood = 15.23 roods
b) Now 1 perch = 16.5 ft
thus,
1 perch² = 16.5² ft² = 272.25 ft²
also 1 m = 3.28 ft
thus,
1 ft = 1/3.28 m
or
1 ft² = (1/3.28 m)² = 0.0929 m²
Now
from (1) we have
Area = 612.921 perch²
612.921 perch² = 612.921 × 272.25 ft² = 166617 ft²
also
166617 ft² = 166617 × 0.0929 m² = 15487.15 m²