Question

a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?

Answer 1

Answer:

The acceleration of the car is $3.13 m/s^2$

Explanation:

In the question it is given that car initially heads north with a velocity $15 m/s$. It then accelerates for $4.25 s$ and in the end its velocity is $28.3 m/s$.

initial velocity $u = 15 m/s$

time $t=4.25 s$

final velocity $v=28.3 m/s$

The equation of acceleration is

$a= \frac{(v-u)}{t}$

$= \frac{(28.3-15)}{4.25} = \frac {13.3}{4.25} =3.13m/s^2$

The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.